Two identical positive point charges, each of magnitude , are fixed in a vacuum at a distance of apart. A third point charge is placed on the perpendicular bisector of the line joining the two fixed charges, at a distance of from their midpoint. Taking Coulomb's constant , what is the magnitude of the net electrostatic force acting on the third charge, in newtons?
Answer: 0.144 N
Answer
The magnitude of the net electrostatic force acting on the third charge is .
Each fixed charge exerts an equal repulsive electrostatic force of on the third charge. Due to the symmetrical arrangement, the force components perpendicular to the bisector cancel each other out, while the parallel components add together, giving a net force of .
Step-by-Step Solution
Key Concept
Vector superposition of Coulombic forces along an axis of symmetry