Question

Difficulty: MediumSimple Machines

A simple machine with a velocity ratio of 55 requires an effort of 200 N200\text{ N} to raise a load of 800 N800\text{ N}. What is the efficiency of the machine in percentage?

Answer: 80% / 80 / 80 percent / 80 %

Answer

The efficiency of the machine is 80%80\%.
The mechanical advantage is calculated by dividing the load (800 N800\text{ N}) by the effort (200 N200\text{ N}), yielding MA=4\text{MA} = 4. Dividing the mechanical advantage by the velocity ratio (55) and multiplying by 100%100\% gives an efficiency of 80%80\%.

Step-by-Step Solution

1
Calculate the Mechanical Advantage (MA) of the machine
MA=LoadEffort=800 N200 N=4\text{MA} = \frac{\text{Load}}{\text{Effort}} = \frac{800\text{ N}}{200\text{ N}} = 4
Mechanical Advantage is defined as the ratio of the force overcome (load) to the force applied (effort).
2
Calculate the Efficiency using Mechanical Advantage and Velocity Ratio
Efficiency=(MAVR)×100%=(45)×100%=80%\text{Efficiency} = \left(\frac{\text{MA}}{\text{VR}}\right) \times 100\% = \left(\frac{4}{5}\right) \times 100\% = 80\%
Efficiency is the ratio of Mechanical Advantage to Velocity Ratio expressed as a percentage.

Key Concept

Efficiency of a Simple Machine
Estimated Time:1m 30s
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