When copper metal turnings are heated with concentrated tetraoxosulfate(VI) acid (), a dense gas is evolved alongside the formation of copper(II) tetraoxosulfate(VI) () and water (). Which of the following correctly identifies the gaseous product evolved and the specific role of concentrated in this chemical reaction?
- Sulfur(IV) oxide (); concentrated acts as an oxidizing agent.Answer
- BHydrogen gas (); concentrated acts as a typical acid reacting with a metal.
- CSulfur(VI) oxide (); concentrated acts as a dehydrating agent.
- DHydrogen sulfide (); concentrated acts as a reducing agent.
Answer
Sulfur(IV) oxide (); concentrated acts as an oxidizing agent.
Copper is an unreactive transition metal located below hydrogen in the electrochemical series. Consequently, it does not react with dilute acids to liberate hydrogen gas. However, when heated with concentrated tetraoxosulfate(VI) acid, the acid behaves as a strong oxidizing agent rather than a typical acid. Copper is oxidized to copper(II) tetraoxosulfate(VI) (), while the sulfur in is reduced from oxidation state to , liberating sulfur(IV) oxide gas () along with water.
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Key Concept
Chemical properties of copper and oxidizing behavior of concentrated tetraoxosulfate(VI) acid
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