Question

Difficulty: MediumCumulative Frequency and Ogive

The frequency distribution table below shows the daily rainfall (in mm) recorded across 8080 weather monitoring stations during a storm:

Daily Rainfall (mm)Frequency (ff)
101910 - 1988
202920 - 291414
303930 - 392626
404940 - 492020
505950 - 591212

Using linear interpolation from the cumulative frequency distribution (ogive), what is the 75th percentile (P75P_{75}) of the daily rainfall in mm?

Answer: 45.5 mm

Answer

The 75th percentile of the daily rainfall distribution is 45.5 mm45.5\text{ mm}.
To find the 75th percentile (P75P_{75}), determine the 60th60^{\text{th}} cumulative frequency position (0.75×80=600.75 \times 80 = 60). The value lies within the 404940 - 49 class interval. Applying the lower class boundary L=39.5L = 39.5, preceding cumulative frequency cfb=48cf_b = 48, frequency f=20f = 20, and class width c=10c = 10, linear interpolation yields P75=39.5+604820×10=45.5 mmP_{75} = 39.5 + \frac{60 - 48}{20} \times 10 = 45.5\text{ mm}.

Step-by-Step Solution

1
Calculate cumulative frequencies across all class intervals.
Cumulative frequencies are 88 for 101910-19, 2222 for 202920-29, 4848 for 303930-39, 6868 for 404940-49, and 8080 for 505950-59. Total frequency N=80N = 80.
Cumulative frequencies are necessary to locate percentile positions on an ogive.
2
Determine the position corresponding to the 75th percentile.
Position =0.75×80=60th= 0.75 \times 80 = 60^{\text{th}} cumulative frequency item.
The 75th percentile represents 75%75\% of the total sample size.
3
Identify the target class interval parameters containing the 60th observation.
The interval 404940 - 49 contains cumulative frequencies from 4949 to 6868. Parameters: L=39.5L = 39.5, c=10c = 10, f=20f = 20, cfb=48cf_b = 48.
Linear interpolation requires the exact boundaries and frequencies of the container class.
4
Apply the percentile interpolation formula P75=L+(60cfbf)×cP_{75} = L + \left(\frac{60 - cf_b}{f}\right) \times c.
P75=39.5+(604820)×10=39.5+6=45.5 mmP_{75} = 39.5 + \left(\frac{60 - 48}{20}\right) \times 10 = 39.5 + 6 = 45.5\text{ mm}.
Calculates the exact rainfall value corresponding to the 75th percentile.

Key Concept

Linear interpolation for percentiles using cumulative frequency distribution (ogive)
Estimated Time:1m 30s
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