Question

Difficulty: EasyMeasurement of Time

A simple pendulum completes 2020 full oscillations in a time interval of 40 s40\text{ s}. What is the period of oscillation of the pendulum in seconds?

Answer: 2 s

Answer

The period of oscillation of the pendulum is 2.0 s2.0\text{ s}.
The period TT of a repeating motion is the time taken to complete one full cycle. Dividing the total measured time (40 s40\text{ s}) by the number of oscillations (2020) gives 2.0 s2.0\text{ s}.

Step-by-Step Solution

1
Identify the given total time and total number of oscillations
Total time t=40 st = 40\text{ s}, number of oscillations N=20N = 20
The period is defined as the time taken for one single complete oscillation.
2
Apply the period formula T=tNT = \frac{t}{N}
T=40 s20=2.0 sT = \frac{40\text{ s}}{20} = 2.0\text{ s}
Dividing the total measured time by the total count of oscillations yields the time per oscillation.

Key Concept

Period of a Simple Pendulum
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