Question

Difficulty: MediumSine and Cosine Rules

In ΔABC\Delta ABC, sinA=35\sin A = \frac{3}{5}, sinB=45\sin B = \frac{4}{5}, and the side opposite angle AA has length a=15 cma = 15\text{ cm}. What is the length of side bb, in centimeters?

Answer: 20 cm

Answer

The length of side bb is 20 cm.
Using the Sine Rule asinA=bsinB\frac{a}{\sin A} = \frac{b}{\sin B}, substitute a=15a = 15, sinA=35\sin A = \frac{3}{5}, and sinB=45\sin B = \frac{4}{5}. Evaluating 153/5\frac{15}{3/5} gives 2525. Multiplying 2525 by 45\frac{4}{5} yields 20 cm20\text{ cm}.

Step-by-Step Solution

1
Set up the Sine Rule relationship between sides aa, bb and their opposite angles AA, BB.
asinA=bsinB\frac{a}{\sin A} = \frac{b}{\sin B}
The Sine Rule relates the side lengths of a triangle to the sines of its angles.
2
Substitute a=15a = 15, sinA=35\sin A = \frac{3}{5}, and sinB=45\sin B = \frac{4}{5} into the Sine Rule equation.
153/5=b4/5\frac{15}{3/5} = \frac{b}{4/5}
Direct substitution of known values allows us to solve for the unknown side bb.
3
Simplify the left side of the equation.
15×53=2515 \times \frac{5}{3} = 25
Dividing 15 by 35\frac{3}{5} is equivalent to multiplying 15 by 53\frac{5}{3}.
4
Multiply both sides by 45\frac{4}{5} to find bb.
b=25×45=20 cmb = 25 \times \frac{4}{5} = 20\text{ cm}
Isolating bb gives the final length of side bb.

Key Concept

Sine Rule
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