Question

Difficulty: EasyElectrical Energy and Power

An electric ceiling fan operates on a 220 V220\,\text{V} mains supply and draws a steady current of 0.5 A0.5\,\text{A}. What is the electrical power rating of the fan?

  1. 110 W110\,\text{W}Answer
  2. B
    440 W440\,\text{W}
  3. C
    220.5 W220.5\,\text{W}
  4. D
    110 J110\,\text{J}

Answer

The electrical power rating of the fan is 110 W110\,\text{W}.
Electrical power PP delivered to a circuit element is given by P=VIP = VI, where VV is potential difference and II is current. Substituting 220 V220\,\text{V} and 0.5 A0.5\,\text{A} gives 110 W110\,\text{W}.

Step-by-Step Solution

1
Identify the given physical quantities
Voltage V=220 VV = 220\,\text{V} and current I=0.5 AI = 0.5\,\text{A}.
These are the basic electrical parameters required to calculate power.
2
Apply the electrical power formula
P=V×IP = V \times I
Electrical power is defined as the product of potential difference across a device and current flowing through it.
3
Substitute values and compute the power
P=220 V×0.5 A=110 WP = 220\,\text{V} \times 0.5\,\text{A} = 110\,\text{W}
Multiplying potential difference by current yields the rate of energy conversion in Watts.

Key Concept

Electrical Power (P=VIP = VI)
Estimated Time:45s
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