An enzyme sample of pepsin extracted from mammalian gastric juice was incubated at with a protein substrate at for two hours, during which no protein hydrolysis occurred. If the mixture is subsequently warmed to while maintaining , which of the following outcomes and explanations is correct?
- Protein digestion proceeds normally because causes temporary inactivation rather than permanent denaturation of the enzyme.Answer
- BNo protein digestion occurs because exposure to permanently denatures the active site of the pepsin molecules.
- CProtein breakdown occurs rapidly into glucose and amino acids via saprophytic extracellular secretion.
- DDigestion occurs only if the is adjusted to neutral to compensate for thermal shock.
Answer
Protein digestion proceeds normally because freezing or low temperature causes temporary inactivation rather than permanent denaturation of the enzyme.
Low temperature () reduces kinetic energy, leading to temporary inactivation of pepsin without damaging its 3D active site conformation. When returned to the body temperature () under its optimal acidic environment (), the enzyme regains kinetic energy and successfully catalyzes the breakdown of proteins into peptides.
Step-by-Step Solution
Key Concept
Effect of temperature and pH on digestive enzyme kinetics (Inactivation vs Denaturation)