Question

Difficulty: MediumPercentage Composition and Percentage Purity Calculations
A 4.20 g4.20\text{ g} sample of impure sodium hydrogentrioxocarbonate(IV), NaHCO3\text{NaHCO}_3, was thermally decomposed according to the equation:
2NaHCO3(s)Na2CO3(s)+H2O(g)+CO2(g)2\text{NaHCO}_3\text{(s)} \rightarrow \text{Na}_2\text{CO}_3\text{(s)} + \text{H}_2\text{O(g)} + \text{CO}_2\text{(g)}
If 0.448 dm30.448\text{ dm}^3 of carbon(IV) oxide gas was collected at s.t.p., what is the percentage purity of the NaHCO3\text{NaHCO}_3 sample? [Na=23,H=1,C=12,O=16,molar volume of gas at s.t.p.=22.4 dm3 mol1][\text{Na} = 23, \text{H} = 1, \text{C} = 12, \text{O} = 16, \text{molar volume of gas at s.t.p.} = 22.4\text{ dm}^3\text{ mol}^{-1}]

Answer: 80 %

Answer

The percentage purity of the sodium hydrogentrioxocarbonate(IV) sample is 80.0%.
The volume of CO₂ gas collected (0.448 dm30.448\text{ dm}^3) corresponds to 0.020 mol0.020\text{ mol} at s.t.p. According to the balanced equation, 2 mol2\text{ mol} of NaHCO3\text{NaHCO}_3 decompose to form 1 mol1\text{ mol} of CO2\text{CO}_2, meaning 0.040 mol0.040\text{ mol} of pure NaHCO3\text{NaHCO}_3 reacted. Multiplying by the molar mass of NaHCO3\text{NaHCO}_3 (84 g mol184\text{ g mol}^{-1}) gives 3.36 g3.36\text{ g} of pure compound, which represents 80.0%80.0\% of the original 4.20 g4.20\text{ g} sample.

Step-by-Step Solution

1
Calculate the moles of carbon(IV) oxide gas evolved at s.t.p.
0.020 mol of CO₂
Dividing the volume of gas collected by the molar volume of a gas at s.t.p. gives the chemical amount in moles.
2
Determine the moles of pure NaHCO₃ using the mole ratio from the balanced chemical equation.
0.040 mol of NaHCO₃
The reaction stoichiometry shows a 2:1 mole ratio between NaHCO₃ and CO₂.
3
Calculate the mass of pure NaHCO₃ by multiplying its moles by its molar mass (84 g/mol).
3.36 g of pure NaHCO₃
Mass is obtained by converting moles to grams using molar mass.
4
Divide the mass of pure NaHCO₃ by the initial mass of the impure sample (4.20 g) and multiply by 100%.
80.0%
Percentage purity expresses the proportion of active compound relative to the total mass of the sample.

Key Concept

Percentage purity calculation based on gas stoichiometry
Estimated Time:1m 30s
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