Question

Difficulty: HardElectrical Energy and Power

A battery of electromotive force (e.m.f.) 24V24\,\text{V} and internal resistance 2Ω2\,\Omega is connected across a parallel network consisting of two resistors of resistances 6Ω6\,\Omega and 12Ω12\,\Omega. What is the total electrical energy, in Joules, dissipated in the external circuit during an operating time of 5minutes5\,\text{minutes}?

Answer: 19200 J

Answer

The total electrical energy dissipated in the external circuit over 5 minutes is 19,200J19,200\,\text{J}.
To compute the external energy dissipated, first combine the parallel resistors to get an equivalent external resistance of 4Ω4\,\Omega. Adding the 2Ω2\,\Omega internal resistance yields a total circuit resistance of 6Ω6\,\Omega, which draws 4A4\,\text{A} of current from the 24V24\,\text{V} battery. The power delivered to the external load is Pext=I2Rp=42×4=64WP_{ext} = I^2 R_p = 4^2 \times 4 = 64\,\text{W}. Multiplying this power by the time duration in seconds (5×60=300s5 \times 60 = 300\,\text{s}) yields 19,200J19,200\,\text{J}.

Step-by-Step Solution

1
Calculate the equivalent resistance of the external parallel circuit
Rp=R1×R2R1+R2=6×126+12=7218=4ΩR_p = \frac{R_1 \times R_2}{R_1 + R_2} = \frac{6 \times 12}{6 + 12} = \frac{72}{18} = 4\,\Omega
The two external resistors are connected in parallel.
2
Calculate the total current supplied by the battery
I=ERp+r=244+2=246=4AI = \frac{E}{R_p + r} = \frac{24}{4 + 2} = \frac{24}{6} = 4\,\text{A}
Ohm's law for a complete circuit accounts for both external resistance and internal resistance.
3
Determine the power dissipated exclusively in the external circuit
Pext=I2Rp=(4)2×4=16×4=64WP_{ext} = I^2 R_p = (4)^2 \times 4 = 16 \times 4 = 64\,\text{W}
Electrical power dissipated across the external load depends on the total current squared times the equivalent external resistance.
4
Convert time from minutes to seconds and calculate total energy dissipated
t=5×60=300st = 5 \times 60 = 300\,\text{s}, E=Pext×t=64×300=19,200JE = P_{ext} \times t = 64 \times 300 = 19,200\,\text{J}
Electrical energy is the product of power in Watts and time in seconds.

Key Concept

Electrical Energy and Power in Circuits with Internal Resistance
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