Question

Difficulty: EasyCompound Events and Probability Laws

Two independent events, AA and BB, have probabilities P(A)=0.4P(A) = 0.4 and P(B)=0.5P(B) = 0.5. What is the probability that both event AA and event BB occur, P(AB)P(A \cap B)?

Answer: 0.2

Answer

The probability that both events occur is 0.2.
For independent events, the joint probability of both events occurring simultaneously is found by multiplying their individual probabilities: P(AB)=P(A)×P(B)=0.4×0.5=0.2P(A \cap B) = P(A) \times P(B) = 0.4 \times 0.5 = 0.2.

Step-by-Step Solution

1
Identify event independence and the required probability operation
Events AA and BB are independent, and the question requires calculating their intersection P(AB)P(A \cap B).
The problem explicitly states that the events are independent.
2
Apply the multiplication law for independent events
P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)
For any two independent events, the probability of both occurring together is the product of their individual probabilities.
3
Perform the multiplication
P(AB)=0.4×0.5=0.2P(A \cap B) = 0.4 \times 0.5 = 0.2
Multiplying 0.4 by 0.5 gives 0.2.

Key Concept

Multiplication Law of Probability for Independent Events
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