Question

Difficulty: HardIndices and Logarithms

What is the numerical value of the expression log⁡2(log⁡381)+log⁡5(1125)+4log⁡23\log_2(\log_3 81) + \log_5\left(\frac{1}{125}\right) + 4^{\log_2 3}?

Answer: 8

Answer

8
Evaluating each term individually: the nested logarithm log⁡2(log⁡381)=log⁡24=2\log_2(\log_3 81) = \log_2 4 = 2; the reciprocal log argument log⁡5(1/125)=−3\log_5(1/125) = -3; and the exponential log power 4log⁡23=(2log⁡23)2=32=94^{\log_2 3} = (2^{\log_2 3})^2 = 3^2 = 9. Combining these gives 2−3+9=82 - 3 + 9 = 8.

Step-by-Step Solution

1
Evaluate the first component log⁡2(log⁡381)\log_2(\log_3 81)
2
Since 81=3481 = 3^4, the inner expression log⁡381=4\log_3 81 = 4, and subsequently log⁡24=2\log_2 4 = 2.
2
Evaluate the second component log⁡5(1125)\log_5\left(\frac{1}{125}\right)
-3
Since 1125=5−3\frac{1}{125} = 5^{-3}, applying the power law of logarithms gives −3-3.
3
Evaluate the third component 4log⁡234^{\log_2 3}
9
Rewrite 44 as 222^2 to obtain (2log⁡23)2=32=9(2^{\log_2 3})^2 = 3^2 = 9 using the fundamental identity alog⁡ab=ba^{\log_a b} = b.
4
Sum the results of the three components
8
Calculate 2+(−3)+9=82 + (-3) + 9 = 8.

Key Concept

Properties of logarithms including change of power, negative exponents, and logarithm exponentiation identities
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