An arithmetic progression (A.P.) has a first term of 8 and a common difference of 6. What … — JAMB UTME

An arithmetic progression (A.P.) has a first term of $8$ and a common difference of $6$ . What is the $9^{\text{th}}$ term of the progression?

The

9^{\text{th}}

term of the arithmetic progression is

56

The

n^{\text{th}}

term of an arithmetic progression is given by

T_n = a + (n - 1)d

. Substituting

a = 8

d = 6

, and

n = 9

yields

T_9 = 8 + (9 - 1) \times 6 = 8 + 48 = 56

Identify the given terms from the problem

First term

a = 8

, common difference

d = 6

, and term position

n = 9

These are the parameters required for the

n^{\text{th}}

term formula of an A.P.

Apply the

n^{\text{th}}

term formula

T_n = a + (n - 1)d

T_9 = 8 + (9 - 1) \times 6

The

n^{\text{th}}

term requires multiplying the common difference by

(n - 1)

Simplify the expression

T_9 = 8 + 8 \times 6 = 8 + 48 = 56

Perform multiplication before addition according to standard order of operations.

General term of an Arithmetic Progression

Question