Question

Difficulty: MediumFinancial Mathematics (Interest, Profit, Loss, and Depreciation)

A cooperative society invested 80,000\text{₦}80,000 in a fixed deposit fund that pays compound interest at a rate of 10%10\% per annum compounded annually. What is the total compound interest earned by the cooperative society at the end of 22 years?

  1. A
    16,000\text{₦}16,000
  2. 16,800\text{₦}16,800Answer
  3. C
    96,000\text{₦}96,000
  4. D
    96,800\text{₦}96,800

Answer

16,800\text{₦}16,800
Using the compound interest formula for total amount, A=P(1+r100)nA = P\left(1 + \frac{r}{100}\right)^n, with principal P=80,000P = \text{₦}80,000, rate r=10%r = 10\%, and time n=2n = 2 years: A=80000×(1.1)2=96,800A = 80000 \times (1.1)^2 = \text{₦}96,800. The interest earned is the difference between the total amount and the principal: I=9680080000=16,800I = 96800 - 80000 = \text{₦}16,800.

Step-by-Step Solution

1
Calculate the total accumulated amount AA using the compound interest formula A=P(1+r100)nA = P\left(1 + \frac{r}{100}\right)^n
A=80000×(1+10100)2=80000×(1.1)2=80000×1.21=96,800A = 80000 \times \left(1 + \frac{10}{100}\right)^2 = 80000 \times (1.1)^2 = 80000 \times 1.21 = \text{₦}96,800
The formula yields the full final balance after compound growth over 2 years.
2
Subtract the initial principal PP from the total amount AA to find the compound interest earned II
I=AP=9680080000=16,800I = A - P = 96800 - 80000 = \text{₦}16,800
Interest earned represents only the financial growth beyond the starting capital.

Key Concept

Compound Interest and Total Accumulated Amount
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