Question

Difficulty: EasyGay-Lussac's Law of Combining Volumes and Avogadro's Law

Complete the statement by calculating the required gas volume under constant temperature and pressure conditions.

Answer:According to Gay-Lussac's law of combining volumes, in the reaction 2CO(g)+O2(g)2CO2(g)2CO_{(g)} + O_{2(g)} \rightarrow 2CO_{2(g)}, 40 cm340\text{ cm}^3 of carbon(II) oxide gas requires exactly 【20】 cm3\text{cm}^3 of oxygen gas for complete reaction.

Answer

20
According to Gay-Lussac's law of combining volumes, gases react in volumes that bear a simple whole-number ratio to one another at constant temperature and pressure. In the balanced equation 2CO(g)+O2(g)2CO2(g)2CO_{(g)} + O_{2(g)} \rightarrow 2CO_{2(g)}, the volume combining ratio of COCO to O2O_2 is 2:12:1. Therefore, 40 cm340\text{ cm}^3 of COCO requires 40 cm32=20 cm3\frac{40\text{ cm}^3}{2} = 20\text{ cm}^3 of O2O_2 for complete combustion.

Step-by-Step Solution

1
Determine the stoichiometric volume ratio from the balanced chemical equation.
2 volumes of CO(g)CO_{(g)} react with 1 volume of O2(g)O_{2(g)}.
By Gay-Lussac's law of combining volumes, the combining volumes of reacting gases at constant temperature and pressure are proportional to their stoichiometric coefficients.
2
Calculate the volume of oxygen needed to react with 40 cm340\text{ cm}^3 of carbon(II) oxide.
Volume of O2(g)=40 cm3×12=20 cm3O_{2(g)} = 40\text{ cm}^3 \times \frac{1}{2} = 20\text{ cm}^3.
Since the ratio of COCO to O2O_2 is 2:12:1, the required volume of O2O_2 is half the volume of COCO.

Key Concept

Gay-Lussac's Law of Combining Volumes
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