Question

Difficulty: MediumSimple Machines

A wheel and axle machine has a wheel of radius 25 cm25\text{ cm} and an axle of radius 5 cm5\text{ cm}. If an effort force of 100 N100\text{ N} is applied to lift a load of 400 N400\text{ N}, what is the efficiency of the machine?

  1. 80%80\%Answer
  2. B
    125%125\%
  3. C
    20%20\%
  4. D
    5%5\%

Answer

The efficiency of the wheel and axle machine is 80%80\%.
First, calculate the velocity ratio as the ratio of wheel radius to axle radius: VR=255=5\text{VR} = \frac{25}{5} = 5. Next, calculate mechanical advantage as load over effort: MA=400100=4\text{MA} = \frac{400}{100} = 4. Finally, calculate efficiency by dividing mechanical advantage by velocity ratio: Efficiency=45×100%=80%\text{Efficiency} = \frac{4}{5} \times 100\% = 80\%.

Step-by-Step Solution

1
Calculate the Velocity Ratio (VR) of the wheel and axle system
VR=Radius of WheelRadius of Axle=25 cm5 cm=5\text{VR} = \frac{\text{Radius of Wheel}}{\text{Radius of Axle}} = \frac{25\text{ cm}}{5\text{ cm}} = 5
For a wheel and axle, the velocity ratio is the ratio of the radius of the wheel to the radius of the axle.
2
Calculate the Mechanical Advantage (MA) of the machine
MA=LoadEffort=400 N100 N=4\text{MA} = \frac{\text{Load}}{\text{Effort}} = \frac{400\text{ N}}{100\text{ N}} = 4
Mechanical advantage measures the force magnification of a machine, defined as the ratio of load raised to effort applied.
3
Calculate the Efficiency of the machine
Efficiency=MAVR×100%=45×100%=80%\text{Efficiency} = \frac{\text{MA}}{\text{VR}} \times 100\% = \frac{4}{5} \times 100\% = 80\%
Efficiency is defined as the ratio of Mechanical Advantage to Velocity Ratio expressed as a percentage.

Key Concept

Efficiency of Simple Machines
Rate this question