Question

Difficulty: MediumDirect, Inverse, Joint and Partial Variation

The total cost CC of printing a school magazine is partly constant and partly varies directly as the number of copies nn printed. If it costs N70,000\text{N}70,000 to print 500500 copies and N140,000\text{N}140,000 to print 1,2001,200 copies, what is the cost of printing 2,0002,000 copies?

  1. A
    N200,000\text{N}200,000
  2. N220,000\text{N}220,000Answer
  3. C
    N240,000\text{N}240,000
  4. D
    N280,000\text{N}280,000

Answer

N220,000\text{N}220,000
In partial variation, the total cost CC is represented by C=k1+k2nC = k_1 + k_2 n. Subtracting the two linear equations 70,000=k1+500k270,000 = k_1 + 500 k_2 and 140,000=k1+1,200k2140,000 = k_1 + 1,200 k_2 gives 700k2=70,000700 k_2 = 70,000, so k2=100k_2 = 100. Substituting k2=100k_2 = 100 yields the fixed constant k1=20,000k_1 = 20,000. Substituting n=2,000n = 2,000 into C=20,000+100nC = 20,000 + 100n yields 20,000+200,000=N220,00020,000 + 200,000 = \text{N}220,000.

Step-by-Step Solution

1
Set up the partial variation equation
C=k1+k2nC = k_1 + k_2 n, where k1k_1 is the fixed cost and k2k_2 is the rate per copy
Partial variation consists of a constant term and a term that varies directly with the independent variable.
2
Substitute given values to form simultaneous equations
Equation 1: 70,000=k1+500k270,000 = k_1 + 500 k_2
Equation 2: 140,000=k1+1,200k2140,000 = k_1 + 1,200 k_2
Using the two given data points (n=500,C=70,000)(n=500, C=70,000) and (n=1,200,C=140,000)(n=1,200, C=140,000) creates a system of linear equations.
3
Solve for the variation constants k1k_1 and k2k_2
Subtracting Equation 1 from Equation 2 gives 70,000=700k2    k2=10070,000 = 700 k_2 \implies k_2 = 100.
Substituting k2=100k_2 = 100 into Equation 1 gives 70,000=k1+500(100)    k1=20,00070,000 = k_1 + 500(100) \implies k_1 = 20,000.
Determines the specific values for the fixed overhead and rate per copy.
4
Calculate the total cost for 2,0002,000 copies
C=20,000+100(2,000)=20,000+200,000=N220,000C = 20,000 + 100(2,000) = 20,000 + 200,000 = \text{N}220,000
Evaluates the completed formula C=20,000+100nC = 20,000 + 100n at n=2,000n = 2,000.

Key Concept

Partial Variation and Simultaneous Equations
Estimated Time:1m 30s
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