Question

Difficulty: EasyMatrices and Determinants

If the matrix M=(2x436)M = \begin{pmatrix} 2x & 4 \\ 3 & 6 \end{pmatrix} is a singular matrix, what is the value of xx?

  1. 11Answer
  2. B
    1-1
  3. C
    22
  4. D
    00

Answer

The value of xx is 11.
A matrix is singular when its determinant equals zero. Evaluating the determinant of (2x436)\begin{pmatrix} 2x & 4 \\ 3 & 6 \end{pmatrix} gives (2x)(6)(4)(3)=12x12(2x)(6) - (4)(3) = 12x - 12. Setting 12x12=012x - 12 = 0 leads directly to x=1x = 1.

Step-by-Step Solution

1
Recall the condition for a matrix to be singular.
A matrix is singular if and only if its determinant is equal to zero, so det(M)=0\det(M) = 0.
Singular matrices have no inverse because their determinant is zero.
2
Calculate the determinant of matrix M=(2x436)M = \begin{pmatrix} 2x & 4 \\ 3 & 6 \end{pmatrix}.
\det(M) = (2x)(6) - (4)(3) = 12x - 12.
The determinant of a 2×22 \times 2 matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix} is adbcad - bc.
3
Set the determinant equal to zero and solve for xx.
12x12=0    12x=12    x=112x - 12 = 0 \implies 12x = 12 \implies x = 1.
Solving the linear equation yields the required parameter value.

Key Concept

Condition for Singular Matrix and 2x2 Determinant Evaluation
Estimated Time:45s
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