Question

Difficulty: Very hardContour Lines and Relief Representation

On a topographical map drawn to a scale of 1:100,0001:100,000, a hill summit is marked with a spot height of 520 m520\text{ m}. The terrain features uniform contour intervals of 20 m20\text{ m}. Point XX is located on the fifth contour line directly below the summit. Point YY is situated at a lower elevation such that the vertical difference in height between Point XX and Point YY is 240 m240\text{ m}. If the straight-line distance measured between Point XX and Point YY on the map is 6 cm6\text{ cm}, calculate the average gradient between Point XX and Point YY expressed in the ratio 1:n1 : n. What is the value of nn?

Answer: 25

Answer

The value of nn is 25, corresponding to an average gradient of 1:251 : 25 (or 1 in 25).
To find the denominator nn of the gradient ratio 1:n1:n, the vertical interval (VI = 240 m240\text{ m}) is compared to the horizontal equivalent (HE = 6,000 m6,000\text{ m}). Dividing 6,000 m6,000\text{ m} by 240 m240\text{ m} yields 2525, meaning the slope rises 1 meter vertically for every 25 meters horizontally.

Step-by-Step Solution

1
Determine the elevation of Point X from the contour interval and spot height.
Elevation of Point X = 520 m(5×20 m)=420 m520\text{ m} - (5 \times 20\text{ m}) = 420\text{ m}.
Point X lies on the fifth contour line below the 520 m520\text{ m} summit with a 20 m20\text{ m} interval.
2
Identify the Vertical Interval (VI) between Point X and Point Y.
VI=240 m\text{VI} = 240\text{ m}.
The vertical elevation difference is directly specified in the problem statement.
3
Convert map distance to actual ground horizontal distance (Horizontal Equivalent, HE) using the map scale.
HE=6 cm×100,000=600,000 cm=6,000 m\text{HE} = 6\text{ cm} \times 100,000 = 600,000\text{ cm} = 6,000\text{ m}.
Unit conversions must align VI and HE in meters before computing the ratio.
4
Express the gradient as a ratio 1:n1 : n by dividing HE by VI.
n=HEVI=6,000 m240 m=25n = \frac{\text{HE}}{\text{VI}} = \frac{6,000\text{ m}}{240\text{ m}} = 25.
Gradient ratio is defined as Vertical IntervalHorizontal Equivalent=1n\frac{\text{Vertical Interval}}{\text{Horizontal Equivalent}} = \frac{1}{n}.

Key Concept

Gradient Calculation and Unit Alignment from Topographical Maps
Estimated Time:2m 30s
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