Question

Difficulty: MediumPopulation Distribution and Density Factors

An administrative district in West Africa has a total population of 450,000450,000 people and a total surface area of 3,000 km23,000\text{ km}^2. If 1,000 km21,000\text{ km}^2 of the district's land area is arable and used for crop cultivation while the remaining 2,000 km22,000\text{ km}^2 is non-arable, what is the physiological population density of this district?

  1. 450 persons per km2450\text{ persons per km}^2Answer
  2. B
    150 persons per km2150\text{ persons per km}^2
  3. C
    225 persons per km2225\text{ persons per km}^2
  4. D
    0.0022 km2 per person0.0022\text{ km}^2\text{ per person}

Answer

The physiological population density of the district is 450 persons per km2450\text{ persons per km}^2.
Physiological density is defined as the ratio of total population to the area of arable land. Dividing the total population of 450,000450,000 inhabitants by the 1,000 km21,000\text{ km}^2 of arable land yields 450 persons per km2450\text{ persons per km}^2.

Step-by-Step Solution

1
Identify the given demographic and land area values
Total population = 450,000450,000; Total land area = 3,000 km23,000\text{ km}^2; Arable land area = 1,000 km21,000\text{ km}^2.
Physiological density specifically relates population to arable (cultivable) land.
2
Apply the physiological density formula
Physiological Density=Total PopulationArable Land Area=450,0001,000 km2=450 persons per km2\text{Physiological Density} = \frac{\text{Total Population}}{\text{Arable Land Area}} = \frac{450,000}{1,000\text{ km}^2} = 450\text{ persons per km}^2
Unlike arithmetic density, physiological density evaluates population pressure specifically on agricultural land resources.

Key Concept

Physiological Population Density vs Arithmetic Population Density
Estimated Time:1m 30s
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