Ammonia gas () reacts with oxygen gas () over a platinum-rhodium catalyst to form nitrogen(II) oxide () and water vapor () according to the equation:
Which of the following statements correctly interprets the oxidation process occurring in this reaction from both classical and modern redox perspectives?
- Ammonia is oxidized because nitrogen loses hydrogen classically, which corresponds to an increase in the oxidation state of nitrogen from to .Answer
- BOxygen gas is reduced because elemental starts with an oxidation state of and gains hydrogen to form .
- CAmmonia acts as an oxidizing agent because nitrogen loses electrons, resulting in a decrease in its oxidation state.
- DOxygen gas acts as a reducing agent because its oxidation number increases from to as it forms water.
Answer
Ammonia is oxidized because nitrogen loses hydrogen classically, which corresponds to an increase in the oxidation state of nitrogen from to .
In classical terminology, oxidation involves the removal of hydrogen or addition of oxygen. Ammonia () loses hydrogen to form nitrogen(II) oxide (), fulfilling classical oxidation. In modern electronic terms, the oxidation number of nitrogen increases from in to in , representing a loss of 5 electrons per nitrogen atom, which directly aligns with the modern definition of oxidation.
Step-by-Step Solution
Key Concept
Integration of Classical (Hydrogen/Oxygen Transfer) and Modern (Oxidation Number/Electron Transfer) Redox Concepts
Estimated Time:2m 0s