Two parallel lines, and , are situated in a plane with above . A regular polygon of sides has one of its sides, , lying entirely on line . An adjacent side, , extends downwards into the region between and . A line segment is drawn from vertex perpendicular to line , meeting at point . The segment lies inside the interior angle of the polygon and divides into two angles, and , such that . What is the total number of diagonals of this regular polygon?
Answer: 54
Answer
54
Because line L_1 is parallel to line L_2 and BD is perpendicular to L_2, BD is also perpendicular to L_1, making angle ABD equal to 90°. Based on the 3:2 ratio, angle DBC equals 60°, giving a total interior angle of 150°. Solving (n - 2) × 180° / n = 150° yields n = 12 sides. Substituting n = 12 into the diagonal formula n(n - 3) / 2 gives 54 diagonals.
Step-by-Step Solution
Key Concept
Combining parallel line perpendicularity properties, angle partitioning, regular polygon interior angle measure, and diagonal count calculation