Question

Difficulty: Very hardPhysical Quantities, Units and Dimensions

The acoustic intensity SS (defined as power per unit area) of a sound wave propagating through a medium of density ρ\rho at speed vv is given by the empirical relationship S=kAxω2ρvwS = k A^x \omega^2 \rho v^w, where AA is the wave displacement amplitude, ω\omega is the angular frequency, and kk is a dimensionless constant. Using the principles of dimensional analysis, calculate the numerical value of the exponent xx.

Answer: 2

Answer

The numerical value of the exponent xx is 2.
By applying the principle of dimensional homogeneity, the dimensions of intensity [S]=MT3[S] = M T^{-3} are equated to [A]x[ω]2[ρ][v]w=MLx3+wT2w[A]^x [\omega]^2 [\rho] [v]^w = M L^{x - 3 + w} T^{-2 - w}. Equating time exponents yields 3=2w    w=1-3 = -2 - w \implies w = 1. Equating length exponents yields 0=x3+w    x=20 = x - 3 + w \implies x = 2.

Step-by-Step Solution

1
Determine the fundamental dimensions of acoustic intensity SS
[S]=[Power][Area]=ML2T3L2=ML0T3[S] = \frac{[\text{Power}]}{[\text{Area}]} = \frac{M L^2 T^{-3}}{L^2} = M L^0 T^{-3}
Intensity is defined as power delivered per unit surface area perpendicular to the direction of propagation.
2
Write the dimensional formulas for all variables in the given equation S=kAxω2ρ1vwS = k A^x \omega^2 \rho^1 v^w
[A]=L[A] = L, [ω]=T1[\omega] = T^{-1}, [ρ]=ML3[\rho] = M L^{-3}, [v]=LT1[v] = L T^{-1}
Each physical quantity must be resolved into fundamental SI dimensions of Mass (MM), Length (LL), and Time (TT).
3
Formulate the dimensional balance equation
M1L0T3=LxT2M1L3LwTw=M1Lx3+wT2wM^1 L^0 T^{-3} = L^x \cdot T^{-2} \cdot M^1 L^{-3} \cdot L^w T^{-w} = M^1 L^{x - 3 + w} T^{-2 - w}
For physical validity, the dimensions on both sides of an equation must be identical (principle of dimensional homogeneity).
4
Equate the exponents of Time (TT) to solve for ww
3=2w    w=1-3 = -2 - w \implies w = 1
The power of TT on the left side must equal the sum of powers of TT on the right side.
5
Equate the exponents of Length (LL) to find xx
0=x3+w    0=x3+1    x=20 = x - 3 + w \implies 0 = x - 3 + 1 \implies x = 2
Substituting w=1w = 1 into the length exponent balance yields the value of xx.

Key Concept

Principle of Dimensional Homogeneity
Estimated Time:2m 0s
Rate this question