Calculate the solubility of the salt in the given solution and complete the statement belo… — JAMB UTME

Calculate the solubility of the salt in the given solution and complete the statement below.

Answer:If

5.85\text{ g}

of sodium chloride (

\text{NaCl}

) is dissolved in water to prepare

250\text{ cm}^3

of a saturated solution at

25^\circ\text{C}

, the solubility of

\text{NaCl}

is 【0.4】

\text{mol/dm}^3

[\text{Na} = 23.0, \text{Cl} = 35.5]

The solubility of sodium chloride at

25^\circ\text{C}

0.4\text{ mol/dm}^3

The solubility in

\text{mol/dm}^3

is obtained by dividing the moles of solute by the solution volume in

\text{dm}^3

. Here,

5.85\text{ g}

\text{NaCl}

corresponds to

0.1\text{ mol}

(

5.85 / 58.5

), and

250\text{ cm}^3

equals

0.25\text{ dm}^3

. Dividing

0.1\text{ mol}

0.25\text{ dm}^3

gives

0.4\text{ mol/dm}^3

Calculate the molar mass of sodium chloride (

\text{NaCl}

Molar mass

= 23.0 + 35.5 = 58.5\text{ g/mol}

The molar mass is required to convert mass in grams to amount in moles.

Determine the number of moles of

\text{NaCl}

present.

\text{Moles} = \frac{5.85\text{ g}}{58.5\text{ g/mol}} = 0.1\text{ mol}

Solubility in

\text{mol/dm}^3

requires the quantity of solute in moles.

Convert the volume of solution from

\text{cm}^3

\text{dm}^3

\text{Volume} = \frac{250\text{ cm}^3}{1000} = 0.25\text{ dm}^3

Concentration units are per cubic decimeter (

\text{dm}^3

Calculate the molar concentration (solubility).

\text{Solubility} = \frac{0.1\text{ mol}}{0.25\text{ dm}^3} = 0.4\text{ mol/dm}^3

Solubility is calculated as moles of solute divided by volume of solution in

\text{dm}^3

Solubility and Concentration Determination

Estimated Time:45s

Question