Question

Difficulty: HardSurds and Rationalization of Denominators

If x=7+37−3x = \frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} - \sqrt{3}} and y=7−37+3y = \frac{\sqrt{7} - \sqrt{3}}{\sqrt{7} + \sqrt{3}}, determine the numerical value of x2+y2x^2 + y^2.

Answer: 23

Answer

The numerical value of x2+y2x^2 + y^2 is 2323.
Rationalizing xx yields 5+212\frac{5 + \sqrt{21}}{2} and rationalizing yy yields 5−212\frac{5 - \sqrt{21}}{2}. The sum x+yx + y equals 55 and the product xyxy equals 11. Substituting these into x2+y2=(x+y)2−2xyx^2 + y^2 = (x + y)^2 - 2xy gives 52−2(1)=235^2 - 2(1) = 23.

Step-by-Step Solution

1
Rationalize the denominators of xx and yy
x=5+212x = \frac{5 + \sqrt{21}}{2} and y=5−212y = \frac{5 - \sqrt{21}}{2}
Multiply the numerator and denominator by the conjugate of the denominator.
2
Calculate the sum x+yx + y and the product xyxy
x+y=5x + y = 5 and xy=1xy = 1
Summing conjugate surd expressions cancels the radical term, and multiplying them applies the difference of two squares.
3
Evaluate x2+y2x^2 + y^2 using the identity (x+y)2−2xy(x + y)^2 - 2xy
x2+y2=52−2(1)=23x^2 + y^2 = 5^2 - 2(1) = 23
Substituting the known sum and product avoids having to square complex surd expressions directly.

Key Concept

Rationalization of binomial denominators and application of symmetric algebraic identities.
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