Arrange the following sequential biochemical events of the light-independent stage (Calvin cycle) of photosynthesis in the correct chronological order from beginning to end.
- 1Carbon dioxide combines with ribulose 1,5-bisphosphate (RuBP) catalyzed by the enzyme RuBisCO.
- 2An unstable 6-carbon intermediate rapidly splits to yield two molecules of 3-phosphoglyceric acid (PGA).
- 3ATP and NADPH from the light-dependent reactions convert 3-phosphoglyceric acid into glyceraldehyde-3-phosphate (G3P).
- 4Glyceraldehyde-3-phosphate molecules are utilized to synthesize hexose sugars and regenerate RuBP.
Answer
The correct chronological sequence of the Calvin cycle is: Carbon dioxide fixation with RuBP by RuBisCO Formation of 3-phosphoglyceric acid (PGA) Reduction of PGA to glyceraldehyde-3-phosphate (G3P) using ATP and NADPH Synthesis of hexose sugars and regeneration of RuBP.
The Calvin cycle progresses through three main stages: Carbon Fixation, Reduction, and Regeneration. First, carbon dioxide combines with RuBP to produce an unstable 6-carbon intermediate. Second, this intermediate breaks down into two molecules of 3-phosphoglycerate (PGA). Third, PGA is phosphorylated and reduced by ATP and NADPH to form glyceraldehyde-3-phosphate (G3P). Finally, G3P is used to produce carbohydrates such as glucose and to regenerate RuBP so the cycle can continue.
Step-by-Step Solution
Key Concept
Calvin cycle sequence: Carbon fixation, cleavage to PGA, reduction to G3P (triose phosphate), and sugar synthesis/RuBP regeneration.