Question

Difficulty: MediumMatrices and Determinants

Given the matrix A=(3142)A = \begin{pmatrix} 3 & 1 \\ 4 & 2 \end{pmatrix}, what is the determinant of the matrix 3A3A?

  1. A
    66
  2. 1818Answer
  3. C
    3030
  4. D
    5454

Answer

The determinant of the matrix 3A3A is 1818.
For any 2×22 \times 2 matrix, scaling the matrix by a factor kk scales its determinant by k2k^2. Since det(A)=(3)(2)(1)(4)=2\det(A) = (3)(2) - (1)(4) = 2, multiplying the matrix by 33 yields det(3A)=32×2=9×2=18\det(3A) = 3^2 \times 2 = 9 \times 2 = 18. Alternatively, computing 3A=(93126)3A = \begin{pmatrix} 9 & 3 \\ 12 & 6 \end{pmatrix} directly gives det(3A)=(9)(6)(3)(12)=5436=18\det(3A) = (9)(6) - (3)(12) = 54 - 36 = 18.

Step-by-Step Solution

1
Calculate the determinant of matrix AA.
\det(A) = (3)(2) - (1)(4) = 6 - 4 = 2.
The determinant of a 2×22 \times 2 matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix} is given by adbcad - bc.
2
Apply the determinant scalar multiplication property for an n×nn \times n matrix.
\det(3A) = 3^2 \det(A) = 9 \times 2 = 18.
For any n×nn \times n square matrix AA and scalar kk, the identity det(kA)=kndet(A)\det(kA) = k^n \det(A) holds. Here, k=3k=3 and n=2n=2.

Key Concept

Scalar Multiplication Property of Determinants
Estimated Time:1m 15s
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