Question

Difficulty: HardSurds and Rationalization of Denominators

If 23−53+5=a+b15\frac{2\sqrt{3} - \sqrt{5}}{\sqrt{3} + \sqrt{5}} = a + b\sqrt{15}, where aa and bb are rational numbers, what is the value of a−ba - b?

  1. −7-7Answer
  2. B
    77
  3. C
    −4-4
  4. D
    −2-2

Answer

−7-7
Rationalizing 23−53+5\frac{2\sqrt{3} - \sqrt{5}}{\sqrt{3} + \sqrt{5}} by multiplying top and bottom by (3−5)(\sqrt{3} - \sqrt{5}) yields 11−315−2=−112+3215\frac{11 - 3\sqrt{15}}{-2} = -\frac{11}{2} + \frac{3}{2}\sqrt{15}. Comparing this with a+b15a + b\sqrt{15} gives a=−112a = -\frac{11}{2} and b=32b = \frac{3}{2}. Computing a−ba - b gives −112−32=−7-\frac{11}{2} - \frac{3}{2} = -7.

Step-by-Step Solution

1
Multiply the numerator and denominator by the conjugate of the denominator (3−5)(\sqrt{3} - \sqrt{5})
(23−5)(3−5)(3+5)(3−5)\frac{(2\sqrt{3} - \sqrt{5})(\sqrt{3} - \sqrt{5})}{(\sqrt{3} + \sqrt{5})(\sqrt{3} - \sqrt{5})}
Rationalizing the denominator requires using the difference of squares.
2
Expand the numerator and simplify the denominator
Numerator: 2(3)−215−15+5=11−3152(3) - 2\sqrt{15} - \sqrt{15} + 5 = 11 - 3\sqrt{15}. Denominator: 3−5=−23 - 5 = -2.
Multiply terms using FOIL and replace (3)2(\sqrt{3})^2 with 33 and (5)2(\sqrt{5})^2 with 55.
3
Divide the numerator by the denominator to express in standard form a+b15a + b\sqrt{15}
11−315−2=−112+3215\frac{11 - 3\sqrt{15}}{-2} = -\frac{11}{2} + \frac{3}{2}\sqrt{15}
Separate the rational term and the surd coefficient.
4
Equate coefficients to find aa and bb, then compute a−ba - b
a=−112,b=32  ⟹  a−b=−112−32=−142=−7a = -\frac{11}{2}, b = \frac{3}{2} \implies a - b = -\frac{11}{2} - \frac{3}{2} = -\frac{14}{2} = -7
Calculate the target expression a−ba - b using the derived rational values.

Key Concept

Rationalization of Binomial Denominators and Equating Surd Coefficients
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