A point moves such that it is equidistant from two parallel lines and , defining locus . A second locus consists of all points that are at a constant distance of units from the fixed point . Calculate the distance between the two points of intersection of locus and locus .
Answer: 6 units
Answer
The distance between the two points of intersection of locus L1 and locus L2 is 6 units.
Locus L1 is the line midway between the two given parallel lines, having the equation 3x - 4y + 5 = 0. Locus L2 is a circle centered at (1, 7) with radius 5. The perpendicular distance from the center (1, 7) to line L1 is 4 units. Applying Pythagoras' theorem to the right triangle formed by the radius, perpendicular distance, and half-chord gives a half-chord length of sqrt(5^2 - 4^2) = 3. Therefore, the distance between the two intersection points (the full chord length) is 2 * 3 = 6 units.
Step-by-Step Solution
Key Concept
Intersection of Loci (Parallel Line Bisector and Circle)
Estimated Time:2m 30s