Question

Difficulty: HardProduction, Propagation, and Classification of Waves

A longitudinal mechanical wave travels through Medium X with a propagation speed of 340 m/s340\text{ m/s}. The distance between two consecutive compressions in Medium X is 0.68 m0.68\text{ m}. When the wave propagates across a boundary into Medium Y, the distance between a compression and the immediately adjacent rarefaction is measured as 1.70 m1.70\text{ m}. What is the speed of propagation of the wave in Medium Y?

  1. 1700 m/s1700\text{ m/s}Answer
  2. B
    850 m/s850\text{ m/s}
  3. C
    340 m/s340\text{ m/s}
  4. D
    680 m/s680\text{ m/s}

Answer

The speed of propagation of the wave in Medium Y is 1700 m/s1700\text{ m/s}.
In Medium X, the distance between consecutive compressions gives a full wavelength of 0.68 m0.68\text{ m}, yielding a wave frequency of f=340 m/s0.68 m=500 Hzf = \frac{340\text{ m/s}}{0.68\text{ m}} = 500\text{ Hz}. Because frequency depends solely on the source, it remains 500 Hz500\text{ Hz} in Medium Y. In Medium Y, the distance between a compression and the adjacent rarefaction is half a wavelength, making λY=2×1.70 m=3.40 m\lambda_Y = 2 \times 1.70\text{ m} = 3.40\text{ m}. Multiplying frequency by the new wavelength gives the speed in Medium Y as vY=500 Hz×3.40 m=1700 m/sv_Y = 500\text{ Hz} \times 3.40\text{ m} = 1700\text{ m/s}.

Step-by-Step Solution

1
Determine the frequency of the wave using parameters from Medium X.
In longitudinal waves, the distance between consecutive compressions equals one wavelength, so λX=0.68 m\lambda_X = 0.68\text{ m}. Using v=fλv = f \cdot \lambda, frequency f=340 m/s0.68 m=500 Hzf = \frac{340\text{ m/s}}{0.68\text{ m}} = 500\text{ Hz}.
Frequency is determined by the wave source and remains unchanged when a wave transitions between different media.
2
Calculate the wavelength of the wave in Medium Y.
The distance from a compression to the immediately adjacent rarefaction is half of a wavelength (λY2=1.70 m\frac{\lambda_Y}{2} = 1.70\text{ m}). Therefore, λY=2×1.70 m=3.40 m\lambda_Y = 2 \times 1.70\text{ m} = 3.40\text{ m}.
A full wavelength spans from compression to compression or rarefaction to rarefaction.
3
Calculate the wave propagation speed in Medium Y.
vY=fλY=500 Hz×3.40 m=1700 m/sv_Y = f \cdot \lambda_Y = 500\text{ Hz} \times 3.40\text{ m} = 1700\text{ m/s}.
Applying the wave speed formula with constant frequency.

Key Concept

Wave Propagation across Boundaries and Longitudinal Wave Characteristics
Estimated Time:2m 0s
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