Question

Difficulty: EasyMatrices and Determinants

If the determinant of the matrix M=(x325)M = \begin{pmatrix} x & 3 \\ 2 & 5 \end{pmatrix} is 1414, find the value of xx.

Answer: 4

Answer

The value of xx is 44.
For matrix M=(x325)M = \begin{pmatrix} x & 3 \\ 2 & 5 \end{pmatrix}, the determinant is calculated as (x)(5)(3)(2)=5x6(x)(5) - (3)(2) = 5x - 6. Equating this to 1414 gives 5x6=145x - 6 = 14, which simplifies to 5x=205x = 20, yielding x=4x = 4.

Step-by-Step Solution

1
Apply the 2×22 \times 2 determinant formula det=adbc\det = ad - bc
\det(M) = (x \times 5) - (3 \times 2) = 5x - 6
The determinant of a 2×22 \times 2 matrix is the product of the main diagonal minus the product of the anti-diagonal.
2
Set the determinant equal to the given value 1414
5x - 6 = 14
The problem states that the determinant is equal to 14.
3
Solve the linear equation for xx
5x = 20 \implies x = 4
Adding 6 to both sides gives 5x=205x = 20, and dividing by 5 yields x=4x = 4.

Key Concept

Determinant of a 2x2 Matrix
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