A shell of total mass is moving horizontally with a velocity of when an internal explosion splits it into two fragments. One fragment of mass is propelled backward along the original path at a speed of . What is the magnitude of the velocity, in , of the second fragment immediately after the explosion?
Answer: 40 m s^-1
Answer
The magnitude of the velocity of the second fragment immediately after the explosion is .
According to the Law of Conservation of Linear Momentum, the total momentum of a system remains constant when no net external horizontal force acts on it. Taking the original direction of motion as positive, the initial momentum is . Since the fragment moves backward at , its momentum is . For total momentum to remain , the remaining fragment must carry a momentum of , which corresponds to a velocity of .
Step-by-Step Solution
Key Concept
Conservation of Linear Momentum in Explosions (1D Vector Sign Convention)