Question

Difficulty: MediumArithmetic and Geometric Progressions (AP and GP)

The sum of the first nn terms of an arithmetic progression (A.P.) is given by Sn=2n2+3nS_n = 2n^2 + 3n. What is the 5th5^{\text{th}} term of the progression?

  1. 2121Answer
  2. B
    6565
  3. C
    4444
  4. D
    2525

Answer

The 5th5^{\text{th}} term of the arithmetic progression is 2121.
The nthn^{\text{th}} term of a sequence can be determined from its sum formula using Tn=SnSn1T_n = S_n - S_{n-1}. Evaluating S5=2(5)2+3(5)=65S_5 = 2(5)^2 + 3(5) = 65 and S4=2(4)2+3(4)=44S_4 = 2(4)^2 + 3(4) = 44, the difference T5=6544=21T_5 = 65 - 44 = 21 gives the correct value of the 5th5^{\text{th}} term.

Step-by-Step Solution

1
Calculate the sum of the first 5 terms (S5S_5)
S5=2(5)2+3(5)=2(25)+15=65S_5 = 2(5)^2 + 3(5) = 2(25) + 15 = 65
To find the sum up to the 5th5^{\text{th}} term using the given formula Sn=2n2+3nS_n = 2n^2 + 3n.
2
Calculate the sum of the first 4 terms (S4S_4)
S4=2(4)2+3(4)=2(16)+12=44S_4 = 2(4)^2 + 3(4) = 2(16) + 12 = 44
To find the cumulative total of all terms prior to the 5th5^{\text{th}} term.
3
Subtract S4S_4 from S5S_5 to isolate the 5th5^{\text{th}} term (T5T_5)
T5=S5S4=6544=21T_5 = S_5 - S_4 = 65 - 44 = 21
The nthn^{\text{th}} term of any sequence is given by the relation Tn=SnSn1T_n = S_n - S_{n-1}.

Key Concept

Relationship between the sum of nn terms (SnS_n) and the nthn^{\text{th}} term (TnT_n) in an Arithmetic Progression
Estimated Time:1m 30s
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