Question

Difficulty: EasyArithmetic and Geometric Progressions (AP and GP)

An arithmetic progression (A.P.) has a fifth term of 1717 and a common difference of 33. What is the first term of the progression?

  1. 55Answer
  2. B
    22
  3. C
    1-1
  4. D
    2929

Answer

The first term of the progression is 55.
Using the nthn^{\text{th}} term formula for an arithmetic progression, Tn=a+(n1)dT_n = a + (n - 1)d, substituting T5=17T_5 = 17, n=5n = 5, and d=3d = 3 gives 17=a+4(3)    17=a+12    a=517 = a + 4(3) \implies 17 = a + 12 \implies a = 5.

Step-by-Step Solution

1
Identify the given parameters and formula for the nthn^{\text{th}} term of an A.P.
Formula: Tn=a+(n1)dT_n = a + (n - 1)d, where T5=17T_5 = 17, n=5n = 5, and d=3d = 3.
The standard formula connects the nthn^{\text{th}} term, first term, term position, and common difference.
2
Substitute the given values into the formula.
17=a+(51)×3    17=a+4×3    17=a+1217 = a + (5 - 1) \times 3 \implies 17 = a + 4 \times 3 \implies 17 = a + 12.
Evaluating (n1)d(n - 1)d gives the total difference added to the first term.
3
Solve for the first term aa.
a=1712=5a = 17 - 12 = 5.
Subtracting 1212 from both sides isolates aa.

Key Concept

Arithmetic Progression nthn^{\text{th}} term calculation
Estimated Time:45s
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