Question

Difficulty: EasySimultaneous Linear and Quadratic Equations

Find the positive value of xx that satisfies the simultaneous equations y=x+2y = x + 2 and y=x24y = x^2 - 4.

Answer: 3

Answer

The positive value of xx is 3.
Equating the linear equation y=x+2y = x + 2 and the quadratic equation y=x24y = x^2 - 4 yields x2x6=0x^2 - x - 6 = 0. Factorizing this quadratic equation gives (x3)(x+2)=0(x - 3)(x + 2) = 0, which yields roots x=3x = 3 and x=2x = -2. Selecting the positive value gives 3.

Step-by-Step Solution

1
Equate the linear and quadratic equations
x+2=x24x + 2 = x^2 - 4
Since both expressions are equal to yy, set them equal to each other to solve for xx.
2
Rearrange into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0
x2x6=0x^2 - x - 6 = 0
Subtract xx and 22 from both sides of the equation.
3
Factorize the quadratic expression
(x3)(x+2)=0(x - 3)(x + 2) = 0
Find two factors of 6-6 that add up to 1-1, which are 3-3 and 22.
4
Determine the roots and select the positive value
x=3x = 3
Setting each factor to zero gives x=3x = 3 or x=2x = -2. Selecting the positive root yields 33.

Key Concept

Solving simultaneous linear and quadratic equations by substitution
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