Question

Difficulty: MediumElectrochemical Series and Reaction Spontaneity
The standard reduction potentials for aluminium and nickel half-cells at 25C25^\circ\text{C} are given below:
Al3+(aq)+3eAl(s)E=1.66 V\text{Al}^{3+}(aq) + 3e^- \rightarrow \text{Al}(s) \quad E^\circ = -1.66\text{ V}
Ni2+(aq)+2eNi(s)E=0.25 V\text{Ni}^{2+}(aq) + 2e^- \rightarrow \text{Ni}(s) \quad E^\circ = -0.25\text{ V}

Calculate the standard electromotive force (EcellE^\circ_{\text{cell}}) in volts for the spontaneous reaction between these two half-cells.

Answer: 1.41 V

Answer

The standard electromotive force (EcellE^\circ_{\text{cell}}) for the spontaneous galvanic cell reaction is +1.41 V.
For a spontaneous electrochemical reaction, the standard cell electromotive force (EcellE^\circ_{\text{cell}}) must be positive. The half-reaction with the more positive standard reduction potential (Ni2+/Ni\text{Ni}^{2+}/\text{Ni} at 0.25 V-0.25\text{ V}) proceeds as a reduction at the cathode. The half-reaction with the less positive potential (Al3+/Al\text{Al}^{3+}/\text{Al} at 1.66 V-1.66\text{ V}) proceeds as an oxidation at the anode. Calculating Ecell=EcathodeEanode=0.25 V(1.66 V)=+1.41 VE^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} = -0.25\text{ V} - (-1.66\text{ V}) = +1.41\text{ V}. Because EE^\circ is an intensive property, the stoichiometric coefficients used to balance electrons (2Al+3Ni2+2Al3++3Ni2\text{Al} + 3\text{Ni}^{2+} \rightarrow 2\text{Al}^{3+} + 3\text{Ni}) do not affect the numerical values of the half-cell potentials.

Step-by-Step Solution

1
Determine which electrode undergoes reduction (cathode) and which undergoes oxidation (anode)
Nickel ion reduction occurs at the cathode (E=0.25 VE^\circ = -0.25\text{ V}), and aluminium metal oxidation occurs at the anode (E=1.66 VE^\circ = -1.66\text{ V}).
A galvanic cell operates spontaneously (Ecell>0E^\circ_{\text{cell}} > 0) when the half-cell with the more positive standard reduction potential acts as the cathode.
2
State the equation for standard cell potential
Ecell=EcathodeEanodeE^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}}
The cell potential measures the potential difference between the reduction half-reaction and the oxidation half-reaction under standard conditions.
3
Substitute the reduction potential values into the equation
Ecell=0.25 V(1.66 V)=+1.41 VE^\circ_{\text{cell}} = -0.25\text{ V} - (-1.66\text{ V}) = +1.41\text{ V}
Standard electrode potentials are intensive properties; hence, balancing electron stoichiometry does not scale EE^\circ values.

Key Concept

Calculating standard cell electromotive force (EcellE^\circ_{\text{cell}}) and predicting spontaneity from standard reduction potentials
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