Question

Difficulty: HardSlope and Gradient Calculation

Match each topographic map slope calculation scenario on the left with its corresponding calculated gradient representation on the right.

  • A vertical rise of 50 m50\text{ m} measured across a map distance of 4 cm4\text{ cm} on a map scale of 1:25,0001 : 25,0001 in 201 \text{ in } 20 (5.0%5.0\%)
  • An elevation change from 120 m120\text{ m} to 320 m320\text{ m} along a road measuring 5 cm5\text{ cm} on a 1:50,0001 : 50,000 topographical map1 in 12.51 \text{ in } 12.5 (8.0%8.0\%)
  • A hill slope rising 150 m150\text{ m} across a map line of 6 cm6\text{ cm} drawn to a scale of 1:25,0001 : 25,0001 in 101 \text{ in } 10 (10.0%10.0\%)
  • A terrain transect crossing 44 contour intervals of 20 m20\text{ m} each, spanning a map distance of 4 cm4\text{ cm} at 1:100,0001 : 100,000 scale1 in 501 \text{ in } 50 (2.0%2.0\%)

Answer

The correct pairings are: (1) A vertical rise of 50 m across 4 cm on a 1:25,000 map matches 1 in 20 (5.0%); (2) An elevation change from 120 m to 320 m over 5 cm on a 1:50,000 map matches 1 in 12.5 (8.0%); (3) A rise of 150 m over 6 cm on a 1:25,000 map matches 1 in 10 (10.0%); (4) Crossing 4 contour intervals of 20 m across 4 cm at 1:100,000 scale matches 1 in 50 (2.0%).
Each scenario is accurately paired by converting the map distance to actual ground distance in meters using the given scale, determining the vertical interval, and computing the gradient as a ratio (1 in N) and percentage.

Step-by-Step Solution

1
Convert the map distance for each scenario into the ground horizontal distance (Horizontal Equivalent, HE) in meters using the designated map scale.
Scenario 1: 4 cm×25,000/100=1,000 m4\text{ cm} \times 25,000 / 100 = 1,000\text{ m}. Scenario 2: 5 cm×50,000/100=2,500 m5\text{ cm} \times 50,000 / 100 = 2,500\text{ m}. Scenario 3: 6 cm×25,000/100=1,500 m6\text{ cm} \times 25,000 / 100 = 1,500\text{ m}. Scenario 4: 4 cm×100,000/100=4,000 m4\text{ cm} \times 100,000 / 100 = 4,000\text{ m}.
Map scale Representative Fractions convert map measurements to real ground horizontal distances, which must be expressed in meters to match the unit of Vertical Interval.
2
Calculate the total height difference (Vertical Interval, VI) in meters for each terrain scenario.
Scenario 1: VI=50 m\text{VI} = 50\text{ m}. Scenario 2: VI=320 m120 m=200 m\text{VI} = 320\text{ m} - 120\text{ m} = 200\text{ m}. Scenario 3: VI=150 m\text{VI} = 150\text{ m}. Scenario 4: VI=4 intervals×20 m=80 m\text{VI} = 4 \text{ intervals} \times 20\text{ m} = 80\text{ m}.
Vertical Interval represents the net vertical relief difference between the start and end points of the transect.
3
Compute the gradient ratio (VI / HE) and express it both as a simple ratio (1 in N) and as a percentage slope.
Scenario 1: 501,000=1201 in 20\frac{50}{1,000} = \frac{1}{20} \rightarrow 1 \text{ in } 20 (5.0%5.0\%). Scenario 2: 2002,500=112.51 in 12.5\frac{200}{2,500} = \frac{1}{12.5} \rightarrow 1 \text{ in } 12.5 (8.0%8.0\%). Scenario 3: 1501,500=1101 in 10\frac{150}{1,500} = \frac{1}{10} \rightarrow 1 \text{ in } 10 (10.0%10.0\%). Scenario 4: 804,000=1501 in 50\frac{80}{4,000} = \frac{1}{50} \rightarrow 1 \text{ in } 50 (2.0%2.0\%).
Gradient formula is Gradient=Vertical Interval (VI)Horizontal Equivalent (HE)\text{Gradient} = \frac{\text{Vertical Interval (VI)}}{\text{Horizontal Equivalent (HE)}}.

Key Concept

Slope and Gradient Calculation from Topographical Maps
Estimated Time:3m 0s
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