Question

Difficulty: EasyArithmetic and Geometric Progressions (AP and GP)

The 3rd3^{\text{rd}} term of a geometric progression (G.P.) is 1818 and its common ratio is 33. What is the first term of the progression?

Answer: 2

Answer

The first term of the geometric progression is 2.
In a geometric progression, the nthn^{\text{th}} term is given by Tn=arn1T_n = a r^{n-1}. For the 3rd3^{\text{rd}} term (n=3n = 3) with common ratio r=3r = 3 and term value 1818, the equation is 18=a32=9a18 = a \cdot 3^{2} = 9a. Dividing by 99 yields the first term a=2a = 2.

Step-by-Step Solution

1
Identify the formula for the nthn^{\text{th}} term of a geometric progression.
Tn=arn1T_n = a r^{n-1}
This formula connects the nthn^{\text{th}} term TnT_n to the first term aa, common ratio rr, and term index nn.
2
Substitute T3=18T_3 = 18, r=3r = 3, and n=3n = 3 into the formula.
18=a331    18=9a18 = a \cdot 3^{3-1} \implies 18 = 9a
Evaluating 331=32=93^{3-1} = 3^2 = 9 simplifies the equation.
3
Solve for the first term aa.
a=189=2a = \frac{18}{9} = 2
Dividing both sides of the equation by 9 isolates the first term.

Key Concept

Geometric Progression nth term calculation
Rate this question