Question

Difficulty: MediumBasic Trigonometric Ratios, Special Angles, and Identities

Without using a calculator, evaluate the exact value of the trigonometric expression:

sin60cos30+cos60sin30tan45+tan260\frac{\sin 60^\circ \cos 30^\circ + \cos 60^\circ \sin 30^\circ}{\tan 45^\circ + \tan^2 60^\circ}
  1. 14\frac{1}{4}Answer
  2. B
    12\frac{1}{2}
  3. C
    34\frac{3}{4}
  4. D
    11

Answer

14\frac{1}{4}
Evaluating each trigonometric ratio using standard special angles (30,45,6030^\circ, 45^\circ, 60^\circ) gives a numerator of (3232)+(1212)=34+14=1\left(\frac{\sqrt{3}}{2} \cdot \frac{\sqrt{3}}{2}\right) + \left(\frac{1}{2} \cdot \frac{1}{2}\right) = \frac{3}{4} + \frac{1}{4} = 1. The denominator is tan45+(tan60)2=1+(3)2=1+3=4\tan 45^\circ + (\tan 60^\circ)^2 = 1 + (\sqrt{3})^2 = 1 + 3 = 4. Dividing the numerator by the denominator yields 14\frac{1}{4}.

Step-by-Step Solution

1
Evaluate special angle values for the numerator
sin60=32\sin 60^\circ = \frac{\sqrt{3}}{2}, cos30=32\cos 30^\circ = \frac{\sqrt{3}}{2}, cos60=12\cos 60^\circ = \frac{1}{2}, and sin30=12\sin 30^\circ = \frac{1}{2}.
Recall exact surd values for special angles 3030^\circ and 6060^\circ.
2
Simplify the numerator expression
(32×32)+(12×12)=34+14=1\left(\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2}\right) + \left(\frac{1}{2} \times \frac{1}{2}\right) = \frac{3}{4} + \frac{1}{4} = 1.
Multiply exact surd values and add fractions.
3
Evaluate special angle values for the denominator
tan45=1\tan 45^\circ = 1 and tan60=3\tan 60^\circ = \sqrt{3}, so tan260=(3)2=3\tan^2 60^\circ = (\sqrt{3})^2 = 3.
Square the exact value of tan60\tan 60^\circ.
4
Simplify the denominator and divide the numerator by the denominator
\text{Denominator} = 1 + 3 = 4, \text{ so overall value} = \frac{1}{4}$.
Divide numerator result by denominator result.

Key Concept

Special Angle Trigonometric Ratios and Exact Value Simplification
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