A beam of monochromatic light strikes a photosensitive metal surface, causing the emission of photoelectrons. If the intensity of the incident light is doubled while maintaining the same frequency, what happens to the stopping potential of the emitted electrons?
- It remains unchangedAnswer
- BIt is doubled
- CIt is quadrupled
- DIt is reduced by half
Answer
The stopping potential remains unchanged because it depends only on the frequency of the incident light, not its intensity.
According to Einstein's photoelectric theory, the maximum kinetic energy of emitted electrons is given by , where is Planck's constant, is the frequency of the incident light, and is the work function of the metal. The stopping potential is related to by . Doubling the intensity of the light increases the number of photons hitting the surface per unit time (thus increasing the photocurrent), but it does not change the energy of individual photons (). Consequently, the maximum kinetic energy and the stopping potential remain completely unchanged.
Step-by-Step Solution
Key Concept
Independence of photoelectron kinetic energy and stopping potential from light intensity