Question

Difficulty: MediumElectric Circuits and Measuring Instruments

A DC supply with an electromotive force (e.m.f.) of 24.0 V24.0\text{ V} and an internal resistance of 2.0 Ω2.0\text{ }\Omega is connected across three identical 12.0 Ω12.0\text{ }\Omega resistors connected in parallel. What is the terminal potential difference across the battery in volts?

Answer: 16 V

Answer

The terminal potential difference across the battery is 16.0 V16.0\text{ V}.
The three identical 12.0 Ω12.0\text{ }\Omega resistors in parallel combine to yield an equivalent external resistance of 4.0 Ω4.0\text{ }\Omega. Adding the battery's internal resistance of 2.0 Ω2.0\text{ }\Omega gives a total circuit resistance of 6.0 Ω6.0\text{ }\Omega. The total current drawn from the battery is I=24.0 V6.0 Ω=4.0 AI = \frac{24.0\text{ V}}{6.0\text{ }\Omega} = 4.0\text{ A}. The terminal potential difference is the voltage drop across the external circuit, V=4.0 A×4.0 Ω=16.0 VV = 4.0\text{ A} \times 4.0\text{ }\Omega = 16.0\text{ V}.

Step-by-Step Solution

1
Find the equivalent external resistance of the three parallel resistors.
Rp=4.0 ΩR_p = 4.0\text{ }\Omega
Three identical resistors R=12.0 ΩR = 12.0\text{ }\Omega connected in parallel have an equivalent resistance of Rp=12.03=4.0 ΩR_p = \frac{12.0}{3} = 4.0\text{ }\Omega.
2
Find the total circuit resistance by adding internal resistance to the parallel combination.
Rtotal=6.0 ΩR_{total} = 6.0\text{ }\Omega
Internal resistance r=2.0 Ωr = 2.0\text{ }\Omega acts in series with the external parallel combination: Rtotal=Rp+r=4.0+2.0=6.0 ΩR_{total} = R_p + r = 4.0 + 2.0 = 6.0\text{ }\Omega.
3
Calculate the total current supplied by the cell.
I=4.0 AI = 4.0\text{ A}
Using the circuit formula I=ERtotalI = \frac{E}{R_{total}}, we divide the e.m.f. of 24.0 V24.0\text{ V} by the total resistance of 6.0 Ω6.0\text{ }\Omega.
4
Compute the terminal potential difference across the cell.
V=16.0 VV = 16.0\text{ V}
The potential drop across the external parallel network is V=IRp=4.0 A×4.0 Ω=16.0 VV = I R_p = 4.0\text{ A} \times 4.0\text{ }\Omega = 16.0\text{ V}, which equals EIr=24.0 V(4.0 A×2.0 Ω)=16.0 VE - Ir = 24.0\text{ V} - (4.0\text{ A} \times 2.0\text{ }\Omega) = 16.0\text{ V}.

Key Concept

Terminal Potential Difference and Internal Resistance
Estimated Time:1m 30s
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