Question

Difficulty: MediumModular Arithmetic

What is the value of (43×15)(mod8)(-43 \times 15) \pmod{8} expressed in standard non-negative remainder form?

  1. 33Answer
  2. B
    5-5
  3. C
    55
  4. D
    3-3

Answer

3
Reducing 43-43 modulo 88 gives 55, and 1515 modulo 88 gives 77. Multiplying these results yields 353(mod8)35 \equiv 3 \pmod{8}, which is the canonical non-negative remainder.

Step-by-Step Solution

1
Reduce individual factors modulo 8
435(mod8)-43 \equiv 5 \pmod{8} (since 43=6×8+5-43 = -6 \times 8 + 5) and 157(mod8)15 \equiv 7 \pmod{8} (since 15=1×8+715 = 1 \times 8 + 7)
Simplifying terms before multiplication makes arithmetic easier.
2
Multiply the reduced remainders
5×7=355 \times 7 = 35
Modular arithmetic preserves multiplication.
3
Reduce the product modulo 8 to obtain the canonical non-negative remainder
35=4×8+3    353(mod8)35 = 4 \times 8 + 3 \implies 35 \equiv 3 \pmod{8}
The final answer in modular arithmetic must fall within the range [0,n1][0, n-1].

Key Concept

Modular Arithmetic and Canonical Non-Negative Remainders
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