Question

Difficulty: Very hardExperimental and Theoretical Probability

In a probability experiment, two fair six-sided dice were rolled 180180 times, yielding an experimental probability of 518\frac{5}{18} for obtaining a sum divisible by 33. If mm additional consecutive rolls were conducted and every single one resulted in a sum divisible by 33, the updated overall experimental probability equaled the theoretical probability that the absolute difference between the numbers shown on two fair six-sided dice is at most 11. Calculate the value of mm.

Answer: 54

Answer

54
The initial number of successful trials is 180×518=50180 \times \frac{5}{18} = 50. The theoretical probability of rolling two dice with an absolute difference of at most 11 is calculated by counting 66 outcomes with difference 00 and 1010 outcomes with difference 11, giving 1636=49\frac{16}{36} = \frac{4}{9}. Equating the updated experimental probability 50+m180+m\frac{50 + m}{180 + m} to 49\frac{4}{9} yields 9(50+m)=4(180+m)9(50 + m) = 4(180 + m), which simplifies to 5m=2705m = 270 or m=54m = 54.

Step-by-Step Solution

1
Calculate the initial number of successful trials from the given experimental probability.
Initial successful outcomes = 180×518=50180 \times \frac{5}{18} = 50.
Experimental probability is defined as the number of successful trials divided by the total number of trials.
2
Calculate the theoretical probability that the absolute difference between two rolled six-sided dice is at most 1.
Favorable outcomes = 16, so P(theoretical)=1636=49P(\text{theoretical}) = \frac{16}{36} = \frac{4}{9}.
Outcomes with difference 0: (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)(1,1), (2,2), (3,3), (4,4), (5,5), (6,6) (6 outcomes). Outcomes with difference 1: (1,2),(2,1),(2,3),(3,2),(3,4),(4,3),(4,5),(5,4),(5,6),(6,5)(1,2), (2,1), (2,3), (3,2), (3,4), (4,3), (4,5), (5,4), (5,6), (6,5) (10 outcomes). Total sample space =6×6=36= 6 \times 6 = 36.
3
Formulate the algebraic equation relating the updated experimental probability to the theoretical probability.
50+m180+m=49\frac{50 + m}{180 + m} = \frac{4}{9}.
Adding mm consecutive successful rolls increases both the number of successful outcomes (to 50+m50 + m) and the total number of trials (to 180+m180 + m).
4
Solve the equation for mm.
9(50+m)=4(180+m)    450+9m=720+4m    5m=270    m=549(50 + m) = 4(180 + m) \implies 450 + 9m = 720 + 4m \implies 5m = 270 \implies m = 54.
Cross-multiplication converts the rational expression into a linear equation.

Key Concept

Experimental and Theoretical Probability Synthesis
Estimated Time:3m 0s
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