Question

Difficulty: MediumLinear and Quadratic Inequalities

Find the sum of all integer values of xx that satisfy both the linear inequality 2x132x - 1 \ge 3 and the quadratic inequality x25x140x^2 - 5x - 14 \le 0.

Answer: 27

Answer

The sum of all integer values of xx satisfying both inequalities is 2727.
Solving the linear inequality 2x132x - 1 \ge 3 yields x2x \ge 2. Solving the quadratic inequality x25x140x^2 - 5x - 14 \le 0 by factoring gives (x7)(x+2)0(x - 7)(x + 2) \le 0, which defines the interval 2x7-2 \le x \le 7. Taking the intersection of x2x \ge 2 and 2x7-2 \le x \le 7 gives 2x72 \le x \le 7. The integer values satisfying this range are 2,3,4,5,6,2, 3, 4, 5, 6, and 77, and their sum is 2727.

Step-by-Step Solution

1
Solve the linear inequality
2x4    x22x \ge 4 \implies x \ge 2
Adding 1 to both sides and dividing by 2 isolates the variable xx.
2
Factor and solve the quadratic inequality
(x7)(x+2)0    2x7(x - 7)(x + 2) \le 0 \implies -2 \le x \le 7
The roots of the quadratic equation are x=7x = 7 and x=2x = -2. The parabola opens upward, so the expression is non-positive between the roots.
3
Determine the intersection of both solution sets
2x72 \le x \le 7
The values of xx must simultaneously satisfy x2x \ge 2 and 2x7-2 \le x \le 7.
4
List all integer solutions within the valid interval
x{2,3,4,5,6,7}x \in \{2, 3, 4, 5, 6, 7\}
These are all the whole numbers contained in the closed interval [2,7][2, 7].
5
Sum the integer solutions
2+3+4+5+6+7=272 + 3 + 4 + 5 + 6 + 7 = 27
Summing the identified integer values yields the final required numerical answer.

Key Concept

Linear and Quadratic Inequalities
Estimated Time:1m 30s
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