Question

Difficulty: Very hardSimple Harmonic Motion

A particle of mass 0.20 kg0.20\text{ kg} executes simple harmonic motion along a straight line. When its displacement from the equilibrium position is 0.03 m0.03\text{ m}, its speed is 0.16 m/s0.16\text{ m/s}. When its displacement is 0.04 m0.04\text{ m}, its speed is 0.12 m/s0.12\text{ m/s}. What is the total mechanical energy of the particle in millijoules (mJ\text{mJ})?

Answer: 4 mJ

Answer

The total mechanical energy of the particle is 4 mJ4\text{ mJ}.
Using the relation v2=ω2(A2x2)v^2 = \omega^2(A^2 - x^2) for the two given state points (0.03 m,0.16 m/s)(0.03\text{ m}, 0.16\text{ m/s}) and (0.04 m,0.12 m/s)(0.04\text{ m}, 0.12\text{ m/s}) forms a set of simultaneous equations. Subtracting them yields ω2=16 rad2/s2\omega^2 = 16\text{ rad}^2/\text{s}^2, leading to A2=0.0025 m2A^2 = 0.0025\text{ m}^2. Substituting these values into E=12mω2A2E = \frac{1}{2}m\omega^2 A^2 gives E=0.004 JE = 0.004\text{ J}, which converts to 4 mJ4\text{ mJ}.

Step-by-Step Solution

1
Set up kinematic equations for both displacement points using v2=ω2(A2x2)v^2 = \omega^2(A^2 - x^2).
0.0256=ω2(A20.0009)0.0256 = \omega^2(A^2 - 0.0009) and 0.0144=ω2(A20.0016)0.0144 = \omega^2(A^2 - 0.0016).
The equation relates linear speed, angular frequency, amplitude, and instantaneous displacement in SHM.
2
Subtract the two simultaneous equations to eliminate A2A^2 and find ω2\omega^2.
0.0112=0.0007ω2    ω2=16 rad2/s20.0112 = 0.0007\omega^2 \implies \omega^2 = 16\text{ rad}^2/\text{s}^2.
Eliminating amplitude isolates the angular frequency squared.
3
Determine A2A^2 by substituting ω2=16\omega^2 = 16 back into one of the state equations.
A2=0.0025 m2    A=0.05 mA^2 = 0.0025\text{ m}^2 \implies A = 0.05\text{ m}.
Amplitude is required to calculate the maximum potential or total mechanical energy.
4
Calculate total mechanical energy E=12mω2A2E = \frac{1}{2}m\omega^2 A^2 and convert to millijoules.
E=12×0.20×16×0.0025=0.004 J=4 mJE = \frac{1}{2} \times 0.20 \times 16 \times 0.0025 = 0.004\text{ J} = 4\text{ mJ}.
Total energy in SHM is constant and proportional to mass, square of angular frequency, and square of amplitude.

Key Concept

Conservation of energy and phase-space relationship between velocity and displacement in simple harmonic motion.
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