A sample of polluted air containing nitrogen dioxide (), carbon dioxide (), and unpolluted air components is passed sequentially through two absorption reagents. First, passing the sample through concentrated sodium hydroxide () solution absorbs both acidic pollutants ( and ), reducing the volume of the gas by . The remaining gas mixture is then passed through alkaline pyrogallol, where oxygen () is completely absorbed, causing a further volume reduction of . Assuming oxygen constitutes by volume of the unpolluted portion of the air sample, what is the percentage by volume of nitrogen dioxide () in the original polluted air sample?
Answer: 8.5 %
Answer
The percentage by volume of nitrogen dioxide (NO₂) in the original polluted air sample is 8.5%.
The absorption of oxygen (75.6 cm³) by alkaline pyrogallol represents 21% of the unpolluted air fraction, giving an unpolluted volume of 360 cm³. The difference between the original sample volume (400 cm³) and unpolluted air volume (360 cm³) represents the total pollutant contraction (40 cm³). Subtracting the 6 cm³ CO₂ contribution leaves 34 cm³ of NO₂, which equals (34 / 400) * 100% = 8.5% by volume.
Step-by-Step Solution
Key Concept
Quantitative determination of air composition and gaseous pollutants via selective volumetric absorption