Question

Difficulty: HardWave Properties and Mathematical Wave Equation

A progressive transverse wave traveling through a primary medium is governed by the mathematical wave equation y=0.05sin(100πt2.5πx)y = 0.05 \sin\left(100\pi t - 2.5\pi x\right), where xx and yy are measured in meters and tt is in seconds. Upon entering a secondary medium, the wave undergoes refraction such that its wavelength decreases by 20%20\%. What is the speed of the wave in the secondary medium in m/s\text{m/s}?

Answer: 32 m/s

Answer

The speed of the wave in the secondary medium is 32 m/s32\text{ m/s}.
Comparing y=0.05sin(100πt2.5πx)y = 0.05 \sin\left(100\pi t - 2.5\pi x\right) with y=Asin(ωtkx)y = A \sin(\omega t - kx) yields ω=100π rad/s\omega = 100\pi\text{ rad/s} and k=2.5π rad/mk = 2.5\pi\text{ rad/m}. This gives a source frequency f=ω2π=50 Hzf = \frac{\omega}{2\pi} = 50\text{ Hz} and initial wavelength λ1=2πk=0.8 m\lambda_1 = \frac{2\pi}{k} = 0.8\text{ m}. Because wave frequency is invariant across boundaries, ff remains 50 Hz50\text{ Hz} in the second medium. The new wavelength is λ2=0.8 m×0.80=0.64 m\lambda_2 = 0.8\text{ m} \times 0.80 = 0.64\text{ m}. Consequently, the wave speed in the second medium is v2=50 Hz×0.64 m=32 m/sv_2 = 50\text{ Hz} \times 0.64\text{ m} = 32\text{ m/s}.

Step-by-Step Solution

1
Extract angular frequency and wave number from the wave equation
ω=100π rad/s\omega = 100\pi\text{ rad/s} and k=2.5π rad/mk = 2.5\pi\text{ rad/m}
Matching coefficients in y=Asin(ωtkx)y = A \sin(\omega t - kx) allows determination of temporal and spatial characteristics.
2
Determine wave frequency and original wavelength
f=50 Hzf = 50\text{ Hz} and λ1=0.8 m\lambda_1 = 0.8\text{ m}
Using fundamental relationships f=ω2πf = \frac{\omega}{2\pi} and λ=2πk\lambda = \frac{2\pi}{k}.
3
Calculate the refracted wavelength under constant frequency
λ2=0.64 m\lambda_2 = 0.64\text{ m} while ff remains 50 Hz50\text{ Hz}
Wave frequency depends solely on the wave source and remains unchanged during medium transitions.
4
Compute wave propagation speed in the new medium
v2=32 m/sv_2 = 32\text{ m/s}
Applying the wave equation v=fλv = f\lambda with the updated wavelength.

Key Concept

Wave equation parameter extraction and frequency invariance during refraction
Estimated Time:2m 0s
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