A metal block of mass 2.5\text{ kg} absorbs 1200\text{ J} of thermal energy, causing its t… — JAMB UTME

A metal block of mass $2.5\text{ kg}$ absorbs $1200\text{ J}$ of thermal energy, causing its temperature to rise by $15\text{ K}$ . What is the heat capacity of the block in $\text{J K}^{-1}$ ?

Answer: 80 J K^-1

Answer

The heat capacity of the block is

80\text{ J K}^{-1}

Heat capacity

C

represents the quantity of heat energy required to raise the temperature of the entire object by

1\text{ K}

. Using the relation

C = \frac{Q}{\Delta T}

, substituting

Q = 1200\text{ J}

and

\Delta T = 15\text{ K}

gives

C = \frac{1200}{15} = 80\text{ J K}^{-1}

Step-by-Step Solution

Identify the given quantities from the problem.

Heat energy

Q = 1200\text{ J}

, temperature change

\Delta T = 15\text{ K}

, and mass

m = 2.5\text{ kg}

Clear identification of parameters is necessary to choose the correct formula.

Apply the formula for heat capacity.

C = \frac{Q}{\Delta T}

Heat capacity

C

measures the heat required to change the temperature of the entire body by

1\text{ K}

, regardless of mass per unit quantity.

Substitute the values to calculate the heat capacity.

C = \frac{1200}{15} = 80\text{ J K}^{-1}

Dividing total thermal energy absorbed by the resulting temperature rise yields the heat capacity.

Key Concept

Heat Capacity (

C = \frac{Q}{\Delta T}

)

Estimated Time:45s

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