A rigid solid object with negligible thermal expansivity is completely submerged in a container of water initially at . The water is then uniformly cooled down to . How does the upthrust (buoyant force) exerted by the water on the submerged object vary during this cooling process?
- It increases to a maximum value at and then decreases as the temperature falls to .Answer
- BIt decreases continuously from down to as the liquid cools.
- CIt remains constant throughout the cooling process because the volume of the submerged object does not change.
- DIt decreases to a minimum value at and then increases as the temperature reaches .
Answer
The upthrust increases to a maximum value at and then decreases as cooling continues to .
According to Archimedes' principle, upthrust is given by . For a submerged object of constant volume, upthrust is directly proportional to the density of water. As water cools from to , it contracts normally, increasing its density to a maximum at (). Upon further cooling from to , water undergoes anomalous expansion, increasing in volume and decreasing in density. Consequently, the upthrust reaches a maximum at and decreases down to .
Step-by-Step Solution
Key Concept
Anomalous expansion of water and its effect on density and upthrust