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13931 questions

Question 6101Question

Geophysical measurements reveal critical physical transitions within Earth's internal structure as well as distinct operational mechanisms across its external spheres. Which of the following options correctly pairs a boundary transition within Earth's interior with an accurate description of a surface process reshaping the external lithosphere?

Show answer & explanation

Answer: The Gutenberg discontinuity marks the boundary between the solid lower mantle and liquid outer core where S-waves cease to propagate, while weathering acts as an in-situ breakdown of surface rocks without direct gravitational transportation.

Answer

The Gutenberg discontinuity marks the boundary between the solid lower mantle and liquid outer core where S-waves cease to propagate, while weathering acts as an in-situ breakdown of surface rocks without direct gravitational transportation.
The Gutenberg discontinuity lies at the boundary between the lower mantle and the outer core (at a depth of around 2900 km2900\text{ km}). Because the outer core is liquid, transverse SS-waves cannot pass through it. Externally, weathering is the static, in-situ breakdown of rock materials on Earth's surface, distinct from downslope mass movement.

Step-by-Step Solution

1
Analyze internal boundary physical properties
The Gutenberg discontinuity occurs at a depth of approximately 2900 km2900\text{ km}, marking the transition from the solid silicate mantle to the liquid iron-nickel outer core. Because secondary (SS) seismic waves cannot travel through liquids, they terminate at this boundary.
Establishing the correct geophysical behavior of seismic waves at Earth's internal boundaries is necessary to evaluate the internal structure component.
2
Evaluate external lithospheric surface processes
Weathering is defined strictly as the static, in-situ physical disintegration and chemical decomposition of rocks exposed at Earth's surface.
Distinguishing weathering from mass movement processes is essential to correctly characterize external sphere dynamics.
3
Synthesize and select the correct pairing
The statement combining the Gutenberg discontinuity SS-wave shear cutoff with in-situ weathering accurately represents both internal and external structural processes.
Matching both validated components identifies the unique correct choice.

Key Concept

Internal Discontinuities and External Lithospheric Processes
Estimated Time:2m 0s
Question 6102Question

In an arid, high-altitude alpine environment experiencing diurnal freeze-thaw cycles and torrential seasonal rainfall, angular rock fragments disintegrate from steep granite cliffs and accumulate at the base. Subsequent heavy rainfall saturates these loose debris accumulations, causing them to flow rapidly down a narrow drainage channel. Which combination of physical weathering and mass wasting processes accurately accounts for this sequence of landscape evolution?

Show answer & explanation

Answer: Frost shattering followed by mudflow

Answer

The initial mechanical disintegration of granite cliffs is caused by frost shattering (frost wedging), and the subsequent rapid downslope movement of saturated debris along a channel is a mudflow.
The correct response correctly identifies frost shattering as the mechanical weathering process driven by freeze-thaw cycles in high-altitude environments, and mudflow as the rapid movement of water-saturated debris down a defined channel.

Step-by-Step Solution

1
Analyze the primary weathering process described in the scenario.
In high-altitude areas with diurnal freeze-thaw temperature fluctuations around 0C0^\circ\text{C}, water trapped in rock joints expands by approximately 9%9\% upon freezing. This exerts internal stress, leading to frost shattering (gelifraction) that detaches angular fragments (scree/talus).
Identifying the specific mechanical weathering process operating under alpine freeze-thaw conditions.
2
Analyze the mass wasting mechanism operating on the accumulated debris.
When sudden torrential rainfall saturates the loose scree fragments, the material behaves as a high-density liquid and surges rapidly down confined channels as a mudflow (or debris flow).
Distinguishing rapid, channelized, water-saturated mass movement from slow or non-fluid slope movements.

Key Concept

Interaction of Frost Wedging and Rapid Channelized Mass Wasting
Estimated Time:2m 0s
Question 6103Question

Which of the following landforms is formed primarily by river deposition in its lower course?

Show answer & explanation

Answer: Delta

Answer

Delta
A delta is formed in the lower course of a river where the gradient flattens and water flow slows down drastically upon reaching a sea or lake. This reduction in velocity causes the stream to deposit its load of sand, silt, and clay at the mouth.

Step-by-Step Solution

1
Identify the stage of the river and process specified in the prompt
The question asks for a feature formed by river deposition in its lower course.
River courses are divided into upper (erosional), middle (transportational/depositional), and lower (predominantly depositional) stages.
2
Evaluate the landform options against the course and process
Deltas are built when a river enters a lake or sea in its lower course, reducing velocity and depositing its sediment load.
Other options represent upper-course erosional features, mass wasting, or metamorphic rock features.

Key Concept

Fluvial Deposition and River Stage Features
Estimated Time:45s
Question 6104Question

A logistics company acquired a commercial delivery truck under a hire purchase agreement. After paying 75% of the total hire purchase price, the company defaulted on two consecutive monthly installments. The owner immediately repossessed the truck from the company's premises without obtaining a court order. Under statutory provisions governing hire purchase, which statement correctly describes the legal position of the owner's action?

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Answer: The repossession is unlawful because once the hirer has paid at least two-thirds of the total hire purchase price, the owner can only enforce repossession through a court order.

Answer

The repossession is unlawful because once the hirer has paid at least two-thirds of the total hire purchase price, the owner can only enforce repossession through a court order.
Under statutory hire purchase law (specifically the Hire Purchase Act), once a hirer has paid a minimum statutory threshold of two-thirds of the total hire purchase price, the owner loses the right to repossess the goods through self-help. Any recovery of the hired property after this threshold must be obtained via a court order. Because the company had paid 75% (which is greater than two-thirds), the owner's self-help repossession without judicial authorization is unlawful.

Step-by-Step Solution

1
Identify the nature of the contract and the proportion of the hire purchase price paid.
The contract is a hire purchase agreement, and the hirer has paid 75% of the total cost.
Statutory rules governing repossession depend directly on the percentage of the hire purchase price already paid.
2
Compare the paid percentage against the statutory repossession threshold under the Hire Purchase Act.
75% exceeds the statutory restriction benchmark of two-thirds (66.67%).
The law protects hirers who have paid a substantial proportion of the purchase price from arbitrary loss of possession.
3
Determine the legality of the owner's extrajudicial repossession.
The owner's direct seizure without a court order is illegal and breaches statutory provisions.
Once the two-thirds threshold is crossed, repossession can only be lawfully effected through judicial proceedings.

Key Concept

Statutory Restrictions on Repossession under the Hire Purchase Act
Question 6105Question

A sole trader who maintains incomplete records wants to convert the system to double-entry bookkeeping in order to prepare the final accounts at the end of the financial year. Arrange the following steps in the correct procedural sequence required to complete this conversion.

Drag items to arrange them in the correct order

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Answer

The correct procedural order is: (1) Prepare the opening Statement of Affairs to determine opening capital, (2) Summarize cash and bank transactions, (3) Construct control accounts for total sales and purchases, (4) Extract a Trial Balance to confirm double-entry accuracy, and (5) Draft the Trading, Profit & Loss Account and Balance Sheet.
Converting single-entry records into full double-entry final accounts requires a strict logical sequence: first, compute opening capital by drawing up an opening Statement of Affairs. Second, summarize cash/bank receipts and payments to trace missing transactions. Third, build Sales and Purchases Ledger Control Accounts to determine total sales and purchases. Fourth, post all double entries and extract a Trial Balance to verify debit-credit agreement. Finally, compile the Trading, Profit & Loss Account and Balance Sheet.

Step-by-Step Solution

1
Determine Opening Capital
Opening Capital = Total Opening Assets − Total Opening Liabilities via the Statement of Affairs.
Without opening capital, the opening ledger accounts cannot be opened under the double-entry framework.
2
Analyze Cash and Bank Records
Cash and bank receipts and payments are analyzed to identify revenue, capital, expense, and drawing transactions.
Cash flow summaries provide essential postings for ledger accounts and control accounts.
3
Calculate Missing Sales and Purchases Figures
Reconstruct Debtors and Creditors Control Accounts to determine total sales and total purchases.
Trading Account requires total turnover (cash sales + credit sales) and total purchases (cash purchases + credit purchases).
4
Post Double Entries and Extract Trial Balance
All ledger balances are summarized in a double-entry Trial Balance.
Arithmetic accuracy of debit and credit balances must be established before proceeding to financial statements.
5
Prepare Financial Statements
Complete Trading, Profit and Loss Account and Statement of Financial Position (Balance Sheet).
This represents the final synthesis of business performance and financial position for the accounting period.

Key Concept

Conversion of Incomplete Records to Double Entry System
Question 6106Question

Identify the specific rural settlement patterns described in the statement below by determining the appropriate geographical terms for the blanks.

Fill in the blanks below

A rural settlement that develops at a focal point where multiple roads converge, causing buildings to extend outwards along each transport route, displays a pattern. Conversely, settlements established on dry point sites in flood-prone environments where buildings are forced to cluster tightly on elevated land exhibit a pattern.
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Answer

Blank 1 is filled by 'star-shaped' (or 'radial') and Blank 2 is filled by 'nucleated' (or 'compact').
The star-shaped (or radial) settlement pattern is characteristic of nodal transport intersections where buildings spread out along several radiating roads. The nucleated (or compact) settlement pattern occurs naturally on dry point sites within poorly drained or flooded areas where limited safe ground forces inhabitants to build closely together.

Step-by-Step Solution

1
Analyze the spatial layout resulting from multiple converging transport routes.
Dwellings expanding along multiple intersecting roads create a star-shaped (radial) pattern outwards from the central junction.
Accessibility along transport axes encourages building alignment along every radiating road.
2
Analyze the physical constraint of dry point sites in marshy or flood-prone areas.
Scarcity of elevated dry land causes dwellings to cluster tightly together into a nucleated (compact) settlement.
Environmental hazards prevent outward dispersion and force high density on available safe ground.

Key Concept

Influence of transport junctions and physical landforms on rural settlement spatial patterns.
Question 6107Question

In the humid tropical zone of southeastern Nigeria, intense seasonal rainfall causes deep leaching of sedimentary rocks, producing acidic, iron-rich ferrallitic soils (red earths) that suffer severe gully erosion upon vegetation clearance. Which of the following best explains why biological conservation measures (such as reforestation and cover cropping) are essential for restoring long-term stability to these specific soils compared to physical terracing alone?

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Answer: Biological measures rebuild organic humus to aggregate porous soil particles and bind loose subsoils against deep hydraulic piping, whereas physical terracing does not improve soil structural cohesion.

Answer

Biological measures rebuild organic humus to aggregate porous soil particles and bind loose subsoils against deep hydraulic piping, whereas physical terracing does not improve soil structural cohesion.
Biological conservation practices like cover cropping and afforestation supply vital organic litter to heavily leached ferrallitic soils. Humus acts as a binding agent to aggregate soil grains, while plant root networks structurally anchor loose subsoils, preventing subsurface piping and gully incision that physical terraces cannot stop on highly permeable sands.

Step-by-Step Solution

1
Identify the pedological characteristics of ferrallitic soils in southern Nigeria.
Ferrallitic soils are heavily leached, kaolinitic red soils derived from sedimentary rocks in high-rainfall zones, possessing poor structural stability and low organic content when stripped of canopy.
Understanding the physical and chemical vulnerability of the soil profile is necessary to evaluate effective conservation methods.
2
Analyze the mechanics of gully erosion in southeastern Nigerian soil formations.
Gully erosion in places like Anambra and Imo is driven by surface runoff and underground water seepage (piping) through porous, un-aggregated sandy subsoil layers beneath steep slopes.
Physical terracing alters slope gradient but does not bind loose subsoil particles or restore lost soil organic matter.
3
Evaluate the specific function of biological soil conservation (reforestation and cover cropping).
Plant roots bind subsoil layers and reduce subterranean piping, while decaying organic litter adds humus that improves soil aggregation, water retention, and structural resistance to erosion.
Biological methods target the root cause of ferrallitic soil degradation by restoring soil structure and vegetative protection.

Key Concept

Ferrallitic Soil Characteristics, Distribution, and Conservation Mechanisms in Nigeria
Question 6108Question

Elite Debaters Club received N60,000\text{N}60,000 in cash as subscription payments from its members during the year ended 31 December 2025. At the end of the year, subscriptions amounting to N8,000\text{N}8,000 were still owing by members. What is the total subscription income to be credited to the Income and Expenditure Account for the year ended 31 December 2025?

Show answer & explanation

Answer: N68,000\text{N}68,000

Answer

N68,000\text{N}68,000
The Income and Expenditure Account operates on the accrual concept of accounting, recognizing income earned during the accounting period irrespective of when cash is received. Subscriptions owing by members at the end of the year (N8,000\text{N}8,000) represent earned income for the current financial year and must be added to cash received (N60,000\text{N}60,000), yielding a total subscription income of N68,000\text{N}68,000.

Step-by-Step Solution

1
Identify cash received for subscriptions during the year
N60,000\text{N}60,000
This is the actual cash inflow recorded in the Receipts and Payments account.
2
Add subscriptions owing (accrued) at the end of the year
N60,000+N8,000=N68,000\text{N}60,000 + \text{N}8,000 = \text{N}68,000
Under the accrual basis of accounting, income earned during the period but not yet received must be included in the Income and Expenditure Account.

Key Concept

Accrual basis adjustment for non-profit organisation subscription income
Question 6109Question

At the end of the financial year, a sole trader's trial balance extracted showed Trade Debtors of 80,000₦80,000 and an existing Provision for Doubtful Debts of 3,000₦3,000. It was decided to write off an additional bad debt of 5,000₦5,000 and maintain a provision for doubtful debts at 5%5\% of the remaining trade debtors. What is the net amount of trade debtors to be presented in the Statement of Financial Position (Balance Sheet)?

Show answer & explanation

Answer: 71250

Answer

The net trade debtors figure to be presented in the Balance Sheet is 71,250₦71,250.
To determine the net trade debtors figure in the Balance Sheet, unrecorded bad debts of 5,000₦5,000 are first written off from gross debtors of 80,000₦80,000, resulting in adjusted debtors of 75,000₦75,000. The required closing provision for doubtful debts is 5%5\% of 75,000₦75,000, which equals 3,750₦3,750. Subtracting this closing provision from adjusted debtors gives 75,0003,750=71,250₦75,000 - ₦3,750 = ₦71,250.

Step-by-Step Solution

1
Calculate Adjusted Trade Debtors
75,000₦75,000
Additional bad debts identified at year-end must be written off from gross trade debtors before calculating the percentage provision for doubtful debts.
2
Calculate Closing Provision for Doubtful Debts
3,750₦3,750
The required 5%5\% provision applies to the adjusted trade debtors (5%×75,0005\% \times ₦75,000).
3
Compute Net Trade Debtors for Financial Statement Presentation
71,250₦71,250
Net trade debtors in the Balance Sheet represents adjusted debtors less the closing provision for doubtful debts (75,0003,750₦75,000 - ₦3,750).

Key Concept

Adjustments for Bad Debts and Provision for Doubtful Debts in Final Accounts
Question 6110Question

A wildlife sanctuary occupies an area of 48 cm248\text{ cm}^2 on a topographical map drawn at a scale of 1:100,0001 : 100,000. If the map is reduced to a new scale of 1:400,0001 : 400,000, what is the area of the sanctuary on the new map in cm2\text{cm}^2?

Show answer & explanation

Answer: 3

Answer

The area of the sanctuary on the reduced map is 3 cm23\text{ cm}^2.
When a map scale is reduced from 1:100,0001 : 100,000 to 1:400,0001 : 400,000, the linear dimension reduces by a factor of 44 (since 100,000400,000=14\frac{100,000}{400,000} = \frac{1}{4}). Because area is two-dimensional, the area changes by the square of the linear reduction factor, which is (14)2=116\left(\frac{1}{4}\right)^2 = \frac{1}{16}. Therefore, the area on the new map is 48 cm2×116=3 cm248\text{ cm}^2 \times \frac{1}{16} = 3\text{ cm}^2.

Step-by-Step Solution

1
Determine the linear scale factor between the original and new scales
Linear scale factor = Original Scale DenominatorNew Scale Denominator=100,000400,000=14\frac{\text{Original Scale Denominator}}{\text{New Scale Denominator}} = \frac{100,000}{400,000} = \frac{1}{4}
When a map scale changes from 1:100,0001 : 100,000 to 1:400,0001 : 400,000, every linear dimension on the map is reduced to 14\frac{1}{4} of its original length.
2
Calculate the area reduction factor
Area scale factor = (14)2=116\left(\frac{1}{4}\right)^2 = \frac{1}{16}
Map area scales as the square of the linear scale factor (n2n^2).
3
Calculate the new area on the reduced map
New Area = 48 cm2×116=3 cm248\text{ cm}^2 \times \frac{1}{16} = 3\text{ cm}^2
Multiplying the original area by the area scale factor gives the area representation on the new map.

Key Concept

Map Reduction and Area Scale Factor Relationship
Question 6111Question

Match each cash book transaction on the left with its correct entry treatment in a two-column cash book on the right.

Click a left item, then click its matching right item

Items

Cash paid into the bank account
Cash received from a trade customer
Cheque issued to pay a trade creditor
Cash withdrawn from the bank for office use

Matches

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Answer

Cash paid into bank matches with Debit Bank column and Credit Cash column (Contra entry); Cash received from customer matches with Debit Cash column; Cheque issued to creditor matches with Credit Bank column; Cash withdrawn from bank for office use matches with Debit Cash column and Credit Bank column (Contra entry).
In a two-column cash book, all cash or cheque receipts are debited to their respective columns, while all cash or cheque payments are credited. Transactions involving the transfer of money between the cash till and the bank account affect both columns simultaneously and are classified as contra entries.

Step-by-Step Solution

1
Apply the double-entry rule for asset accounts (Cash and Bank) in the Cash Book.
Receipts increase asset values and are recorded on the debit side; payments decrease asset values and are recorded on the credit side.
Both Cash and Bank columns function as real/asset accounts.
2
Identify internal movement of funds between Cash and Bank (Contra Entries).
Paying cash into bank debits Bank and credits Cash. Withdrawing bank funds for office cash debits Cash and credits Bank.
When both sides of a transaction are recorded inside the Cash Book itself, it is designated as a Contra entry.
3
Identify direct single-column entries.
Cash received from a customer increases cash (Debit Cash column). Cheque paid to a supplier decreases bank funds (Credit Bank column).
External receipts and payments affect only one column (either Cash or Bank) on one side of the Cash Book.

Key Concept

Two-Column Cash Book Debit/Credit Rules and Contra Entries
Question 6112Question

The following balances were retrieved from the records of Apex Professional Association at the beginning of the financial year:

- Equipment: N200,000\text{N}200,000
- Bank balance: N40,000\text{N}40,000
- Subscriptions in arrears: N10,000\text{N}10,000
- Subscriptions received in advance: N5,000\text{N}5,000
- Accrued electricity expense: N20,000\text{N}20,000

What is the accumulated fund of the association?

Show answer & explanation

Answer: N225,000\text{N}225,000

Answer

N225,000\text{N}225,000
The accumulated fund is equivalent to capital in a profit-making entity, defined as total assets minus total liabilities. Adding equipment (N200,000\text{N}200,000), bank balance (N40,000\text{N}40,000), and subscriptions in arrears (N10,000\text{N}10,000) gives total assets of N250,000\text{N}250,000. Deducting total liabilities comprising subscriptions in advance (N5,000\text{N}5,000) and accrued electricity expense (N20,000\text{N}20,000) gives an accumulated fund of N225,000\text{N}225,000.

Step-by-Step Solution

1
Calculate Total Assets
Total Assets = Equipment (N200,000\text{N}200,000) + Bank balance (N40,000\text{N}40,000) + Subscriptions in arrears (N10,000\text{N}10,000) = N250,000\text{N}250,000
Assets represent all economic resources owned by or owed to the organization.
2
Calculate Total Liabilities
Total Liabilities = Subscriptions in advance (N5,000\text{N}5,000) + Accrued electricity expense (N20,000\text{N}20,000) = N25,000\text{N}25,000
Liabilities represent all amounts owed by the organization to external parties or members.
3
Compute Accumulated Fund
Accumulated Fund = Total Assets (N250,000\text{N}250,000) - Total Liabilities (N25,000\text{N}25,000) = N225,000\text{N}225,000
The accumulated fund of a non-profit organization represents the excess of assets over liabilities.

Key Concept

Accumulated Fund Calculation
Question 6113Question

Arrange the following stages of river capture (stream piracy) in their correct chronological sequence from the initial headward erosion to the final landform development.

Drag items to arrange them in the correct order

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Answer

The correct sequence begins with headward erosion toward the watershed divide, followed by breaching the divide to intercept the weaker stream, the diversion of flow creating an elbow of capture, and finally the formation of a wind gap and misfit stream downstream.
River capture begins when a stream with higher energy or a steeper gradient erodes headward into a watershed divide. Once the divide is breached, the stream intercepts the headwaters of a neighbouring channel. The diverted water creates a sharp bend known as an elbow of capture, while the dry valley below the point of capture becomes a wind gap containing a reduced misfit stream.

Step-by-Step Solution

1
Identify the initial process causing river capture
Headward erosion by the pirate stream with greater erosive power cuts back into the watershed divide.
Unequal gradient or rock resistance causes one stream to extend its valley headward faster than adjacent streams.
2
Determine the moment of interception
The pirate stream cuts through the divide and breaches the upper channel of the adjacent stream.
The divide is eliminated at the lowest col, enabling physical connection between the two drainage systems.
3
Analyze the immediate hydrological redirection
Water from the captured stream flows into the capturing river, forming a sharp right-angled turn called the elbow of capture.
The higher gradient of the pirate stream draws water into its steeper channel.
4
Establish the resulting morphological landforms downstream
The abandoned lower channel retains a wind gap and a misfit stream.
The loss of headwater discharge leaves the former channel oversized relative to its remaining reduced discharge.

Key Concept

River Capture (Stream Piracy) and Drainage Evolution
Question 6114Question

Vanguard Enterprise Plc had an issued share capital of 1,000,0001,000,000 ordinary shares of 0.50\text{₦}0.50 each and a Share Premium account balance of 120,000\text{₦}120,000. The company declared a bonus issue of 11 new ordinary share for every 55 shares held, utilizing the Share Premium account to fund the bonus shares. Immediately following the bonus issue, the company made a rights issue of 11 new ordinary share for every 44 shares held at an issue price of 0.80\text{₦}0.80 per share. What is the final balance of the Share Premium account (in \text{₦}) after both transactions are completed?

Show answer & explanation

Answer: 110000

Answer

The final balance of the Share Premium account after both the bonus issue and rights issue is ₦110,000.
The correct final Share Premium balance is ₦110,000. Funding 200,000 bonus shares of ₦0.50 each requires ₦100,000 from the initial ₦120,000 premium, leaving ₦20,000. Subsequently, the 1-for-4 rights issue on the expanded 1,200,000 shares issues 300,000 shares at a premium of ₦0.30 per share (₦0.80 - ₦0.50), creating ₦90,000 of fresh premium. Summing the remaining ₦20,000 and ₦90,000 gives ₦110,000.

Step-by-Step Solution

1
Calculate the bonus issue share quantity and nominal capital value
200,000 bonus shares with a total nominal value of ₦100,000
A 1-for-5 bonus issue on 1,000,000 shares yields 1,000,000 / 5 = 200,000 shares. At a nominal value of ₦0.50 each, the capital required is 200,000 × ₦0.50 = ₦100,000.
2
Deduct the capitalized amount from the initial Share Premium balance
Remaining Share Premium balance of ₦20,000
Initial Share Premium balance of ₦120,000 minus ₦100,000 capitalized for bonus shares leaves ₦20,000.
3
Determine the expanded share base and calculate the number of rights shares issued
300,000 rights shares issued
Post-bonus issued shares total 1,000,000 + 200,000 = 1,200,000 shares. A 1-for-4 rights issue gives 1,200,000 / 4 = 300,000 shares.
4
Compute the total share premium generated from the rights issue
₦90,000 in new share premium
Rights issue price is ₦0.80 per share while nominal value is ₦0.50, giving a premium of ₦0.30 per share. Total new premium created = 300,000 × ₦0.30 = ₦90,000.
5
Add the new rights issue premium to the remaining Share Premium balance
Total final Share Premium balance of ₦110,000
Remaining balance of ₦20,000 + ₦90,000 new premium = ₦110,000.

Key Concept

Bonus issue capitalization and rights issue share premium calculation
Question 6115Question

Match each rock type in Column I with its correct parent rock or mode of formation in Column II.

Click a left item, then click its matching right item

Items

Marble
Slate
Quartzite
Coal

Matches

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Answer

Marble corresponds to the metamorphism of limestone; Slate corresponds to the metamorphism of clay or shale; Quartzite corresponds to the recrystallization of quartz sandstone; Coal corresponds to the compaction of organic plant remains.
Each rock is matched strictly according to its geological formation process: Marble is metamorphosed limestone, Slate is metamorphosed clay or shale, Quartzite is metamorphosed sandstone, and Coal is formed organically from buried plant matter.

Step-by-Step Solution

1
Determine the origin of Marble
Marble is formed when limestone undergoes metamorphic transformation.
Calcium carbonate grains in limestone recrystallize under heat and pressure into interlocking calcite crystals.
2
Determine the origin of Slate
Slate is derived from shale or clay under low-grade metamorphic conditions.
Directional pressure aligns microscopic clay minerals perpendicular to stress, creating characteristic slaty cleavage.
3
Determine the origin of Quartzite
Quartzite forms from quartz sandstone during metamorphism.
Extreme pressure and heat fuse individual silica sand grains into a continuous crystalline matrix.
4
Determine the origin of Coal
Coal originates from accumulated organic vegetable matter.
Anaerobic decay and continuous burial convert plant debris into peat, lignite, and bituminous coal.

Key Concept

Metamorphic parent rocks (protoliths) and organic sedimentary rock formation
Question 6116Question

Which of the following accounting practices uniquely characterizes an independent branch rather than a dependent branch?

Show answer & explanation

Answer: Extracting a complete trial balance and preparing its own financial statements

Answer

Extracting a complete trial balance and preparing its own financial statements
Extracting a complete trial balance and preparing its own financial statements is the primary feature of an independent branch. Because an independent branch maintains a full set of books using double-entry bookkeeping, it can independently verify the arithmetical accuracy of its ledgers by extracting a trial balance at period-end.

Step-by-Step Solution

1
Identify the accounting autonomy level of an independent branch
An independent branch acts as an autonomous accounting unit keeping full double-entry records.
Independent branches record all transactions, including local purchases, sales, and expenses, in their own ledgers.
2
Determine the financial statement output generated by an independent branch
The branch extracts its own trial balance and prepares its trading and profit and loss accounts.
Extracting a trial balance distinguishes an independent branch from a dependent branch, whose accounts are maintained at the head office.

Key Concept

Accounting distinction between dependent and independent branches
Estimated Time:1m 0s
Question 6117Question

The following details were extracted from the accounting records of Zainab Trading Store for the year ended 31st December 2025:

- Opening debtors balance (1st January 2025): 45,000\text{₦}45,000
- Credit sales for the year: 185,000\text{₦}185,000
- Cash and cheque received from debtors: 142,000\text{₦}142,000
- Dishonoured cheques from debtors: 3,500\text{₦}3,500
- Discount allowed to trade debtors: 4,800\text{₦}4,800
- Bad debts written off: 2,500\text{₦}2,500
- Returns inwards: 6,200\text{₦}6,200
- Set-off against purchases ledger (contra entry): 3,000\text{₦}3,000
- Cash refunded to debtors for overpayment: 1,500\text{₦}1,500

What is the closing debit balance of the Sales Ledger Control Account as at 31st December 2025?

Show answer & explanation

Answer: 76500

Answer

The closing debit balance of the Sales Ledger Control Account as at 31st December 2025 is 76,500\text{₦}76,500.
To find the closing debit balance of the Sales Ledger Control Account, sum all debit entries (Opening Balance 45,000\text{₦}45,000 + Credit Sales 185,000\text{₦}185,000 + Dishonoured Cheques 3,500\text{₦}3,500 + Cash Refunds 1,500\text{₦}1,500 = 235,000\text{₦}235,000) and subtract all credit entries (Cash Received 142,000\text{₦}142,000 + Discount Allowed 4,800\text{₦}4,800 + Bad Debts 2,500\text{₦}2,500 + Returns Inwards 6,200\text{₦}6,200 + Contra Entry 3,000\text{₦}3,000 = 158,500\text{₦}158,500). This gives 235,000158,500=76,500\text{₦}235,000 - \text{₦}158,500 = \text{₦}76,500.

Step-by-Step Solution

1
Calculate the total of the debit side entries
Total Debits = 45,000+185,000+3,500+1,500=��235,000\text{₦}45,000 + \text{₦}185,000 + \text{₦}3,500 + \text{₦}1,500 = \text{��}235,000
Opening debtors balance, credit sales, dishonoured cheques, and refunds to debtors increase the total debt owed by debtors and are placed on the debit side.
2
Calculate the total of the credit side entries
Total Credits = 142,000+4,800+2,500+6,200+3,000=158,500\text{₦}142,000 + \text{₦}4,800 + \text{₦}2,500 + \text{₦}6,200 + \text{₦}3,000 = \text{₦}158,500
Payments received, discounts allowed, bad debts, sales returns, and set-off entries reduce the total debt owed by debtors and are placed on the credit side.
3
Subtract total credit items from total debit items to find the closing balance
Closing Debtors Balance = 235,000158,500=76,500\text{₦}235,000 - \text{₦}158,500 = \text{₦}76,500
The balancing figure on the credit side represents the closing debit balance brought down for the next accounting period.

Key Concept

Sales Ledger Control Account Balancing
Question 6118Question

At the end of a trading period, the total of the discount allowed column in a trader's three-column cash book is 4,500₦4,500, while the total of the discount received column is 3,200₦3,200. How should these column totals be posted to the general ledger?

Show answer & explanation

Answer: Debit Discount Allowed Account with 4,500₦4,500 and credit Discount Received Account with 3,200₦3,200

Answer

Debit Discount Allowed Account with 4,500₦4,500 and credit Discount Received Account with 3,200₦3,200
The correct response reflects standard double-entry bookkeeping rules: the total of the discount allowed column (found on the debit side of the three-column cash book) is debited to the Discount Allowed Account in the general ledger as an expense. Similarly, the total of the discount received column (found on the credit side of the cash book) is credited to the Discount Received Account in the general ledger as income.

Step-by-Step Solution

1
Identify the nature of Discount Allowed
Discount Allowed is an expense incurred when allowing cash discounts to debtors.
Expenses have debit balances and must be debited to their respective account in the general ledger.
2
Identify the nature of Discount Received
Discount Received is income gained when receiving cash discounts from creditors.
Incomes have credit balances and must be credited to their respective account in the general ledger.
3
Determine posting from the Three-Column Cash Book totals
The total of the discount allowed column (4,500₦4,500) is posted to the debit side of Discount Allowed Account, and the total of discount received column (3,200₦3,200) is posted to the credit side of Discount Received Account.
The discount columns in a three-column cash book serve as memo/summary columns, with totals transferred to their general ledger accounts at the end of the period.

Key Concept

Ledger Posting of Cash Book Discount Totals
Estimated Time:1m 0s
Question 6119Question

The cement manufacturing factory at Ewekoro in Ogun State, Nigeria, is situated adjacent to limestone quarries. According to Alfred Weber's industrial location theory, which factor primarily determines the raw-material orientation of such weight-losing industries?

Show answer & explanation

Answer: The weight of the raw material is substantially greater than the weight of the finished product, making transport of raw materials more costly.

Answer

The weight of the raw material is substantially greater than the weight of the finished product, making transport of raw materials more costly.
Cement manufacturing is a classic weight-losing industry. Because raw limestone is bulkier and heavier than the refined cement produced from it, shipping raw limestone over long distances incurs high transport costs. Therefore, establishing the factory near the limestone deposit at Ewekoro minimizes total transportation expenses.

Step-by-Step Solution

1
Identify the industrial classification of cement manufacturing
Cement production uses heavy limestone that loses substantial weight during processing into clinker and cement.
Determining material weight loss establishes the material index under Weber's theory.
2
Apply Weber's least-cost transport principle
Transporting unrefined limestone to distant markets costs significantly more than shipping bagged cement.
Locating the factory near the raw material deposit minimizes overall transportation expenditure.

Key Concept

Weight-losing raw material orientation in industrial location theory
Question 6120Question

Match each physical geography feature below with its corresponding process and landform type.

Click a left item, then click its matching right item

Items

Yardang
Barchan
Cirque
Moraine

Matches

Show answer & explanation

Answer

Yardang matches Aeolian erosional landform produced by wind abrasion; Barchan matches Aeolian depositional crescent-shaped sand dune; Cirque matches Glacial erosional armchair-shaped hollow; Moraine matches Glacial depositional ridge composed of unsorted till.
Each feature is correctly matched to its active agent (wind or moving ice) and whether the process involved is erosional or depositional.

Step-by-Step Solution

1
Identify the primary erosional wind landform
Yardang corresponds to wind abrasion acting on alternating rock strata.
Yardangs are distinct wind-eroded ridges found in arid environments.
2
Identify the primary depositional wind landform
Barchan corresponds to crescent-shaped sand deposition.
Barchans develop under wind action where sand supplies are moderate and winds blow from a single direction.
3
Identify the primary erosional glacial landform
Cirque corresponds to the steep-walled, armchair-shaped mountain hollow.
Cirques are created at the source of mountain glaciers by freeze-thaw weathering and ice plucking.
4
Identify the primary depositional glacial landform
Moraine corresponds to ridges composed of unsorted glacial till.
Moraines are formed when glaciers deposit rock debris as they melt or retreat.

Key Concept

Classification of landforms by geomorphic agent (wind vs glacier) and process (erosion vs deposition)
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